Answer: 2HCO + 4O → H2 + 2CO3
Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide
Reaction Type: SINGLE REPLACEMENT
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Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:

In this case, the percent composition of fluorine is:

percent composition of fluorine= 65.67%
<u><em>The percent composition of fluorine is 65.67%</em></u>
B. sublimation is the answer.
Answer:
The volume will be 18,23 ml.
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. We convert the unit Celsius into Kelvin: 0 ° C = 273K, 44+273=317K, 17+273=290 K. The volume in L= 22/1000= 0,022L
P1xV1/T1= P2xV2/T2
V2= ((P1xV1/T1)xT2)/P2
V2=((0,905 atm x 0,022L/317K)x 290K)/0,999atm= 0,01823 L
0,01823x 1000= 18, 23 ml
<u>Answer:</u> The standard cell potential of the cell is -0.71 V
<u>Explanation:</u>
The half reactions follows:
<u>Oxidation half reaction:</u>
( × 3)
<u>Reduction half reaction:</u>
( × 2)
The balanced cell reaction follows:

To calculate the
of the reaction, we use the equation:

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Putting values in above equation, we get:

Hence, the standard cell potential of the cell is -0.71 V