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sdas [7]
2 years ago
8

I am a subatomic particle that is positively charged what am I?

Chemistry
1 answer:
lions [1.4K]2 years ago
6 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em><u>Proton</u></em><em><u>.</u></em>

<em><u>Additional</u></em><em><u> </u></em><em><u>Information</u></em><em><u>:</u></em>

<em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>three</u></em><em><u> </u></em><em><u>types</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>subatomic</u></em><em><u> </u></em><em><u>particles</u></em><em><u>.</u></em><em><u> </u></em><em><u>They</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>

  1. <em><u>Proton</u></em>
  2. <em><u>Electron</u></em>
  3. <em><u>Neutron</u></em>

<em><u>Proton</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>positively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u>,</u></em><em><u>Electron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>negatively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>Neutron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em><em><u>less</u></em><em><u>.</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Delicious77 [7]

Answer:

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Explanation:

4 0
2 years ago
How do u find ratios of unknown value
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3 years ago
You use 4.98 g of Na2SO4, how many grams of barium sulfate are produced?<br><br> Na2+Ba(NO3)2= ?
Kaylis [27]

Answer:

Mass of barium sulfate = 8.17 g

Explanation:

Given data:

Mass of sodium sulfate = 4.98 g

Mass of barium sulfate produced = ?

Solution:

Na₂SO₄ + Ba(NO₃)₂    →   BaSO₄ + 2NaNO₃

Moles of sodium sulfate:

Number of moles = mass/molar mass

Number of moles =4.98 g / 142.04 g/mol

Number of moles = 0.035 mol

Now we will compare the moles pf sodium sulfate and with barium sulfate.

                            Na₂SO₄               :            BaSO₄

                                1                       :              1

                              0.035                :          0.035

Mass of barium sulfate:

Mass = number of moles × molar mass

Mass =   0.035 mol ×233.4 g/mol

Mass = 8.17 g

6 0
2 years ago
Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H
murzikaleks [220]

Answer:

0.0184

Explanation:

Let's consider the following reaction at equilibrium.

2 HI(g) ⇌ H₂(g) + I₂(g)

The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their  stoichiometric coefficients divided by the product of the concentration of the reactants raised to their  stoichiometric coefficients.

Kc = [H₂] × [I₂] / [HI]²

Kc = (4.78 × 10⁻⁴) × (4.78 × 10⁻⁴) / (3.52 × 10⁻³)²

Kc = 0.0184

5 0
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Answer:

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