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sdas [7]
3 years ago
8

I am a subatomic particle that is positively charged what am I?

Chemistry
1 answer:
lions [1.4K]3 years ago
6 0

<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em><u>Proton</u></em><em><u>.</u></em>

<em><u>Additional</u></em><em><u> </u></em><em><u>Information</u></em><em><u>:</u></em>

<em><u>There</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>three</u></em><em><u> </u></em><em><u>types</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>subatomic</u></em><em><u> </u></em><em><u>particles</u></em><em><u>.</u></em><em><u> </u></em><em><u>They</u></em><em><u> </u></em><em><u>are</u></em><em><u>:</u></em>

  1. <em><u>Proton</u></em>
  2. <em><u>Electron</u></em>
  3. <em><u>Neutron</u></em>

<em><u>Proton</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>positively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u>,</u></em><em><u>Electron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>negatively</u></em><em><u> </u></em><em><u>charged</u></em><em><u> </u></em><em><u>particle</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>Neutron</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em><em><u>less</u></em><em><u>.</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>helpful</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Explanation:

for specific heat we have formula:

Amount of heat absorbed or released = mass x specific heat of a substance x change in temperature.

ΔQ=m x c x ΔT

where c= specific heat

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

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From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

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