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3 years ago

Describe briefly what specific information is given by each of the four quantum numbers

1 answer:

3 0

The following information is given by each four quantum numbers
<span>Main energy level,
Sublevels in main energy levels,
Number of orbitals per </span><span>sublevel,
number of orbitals per main energy level, number of electrons per sublevels
</span>hope it helps

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A 1.00 kg solid, uniform disk rolls without slipping across a level surface, translating at 3.00 m/s. If the disk's radius is 0.

cluponka [151]

Explanation:

Given that,

Mass of the disk, m = 1 kg

Translational speed of the disk, v = 3 m/s

Radius of the disk, r = 0.39 m

(a) Let K is the tranlational kinetic energy of the disk. Its formula is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 1\times 3^2$

K = 4.5 J

(b) Let K' is the rotational kinetic energy of the disk. Its formula is given by :

$K'=\dfrac{1}{2}I\omega^2$

$K'=\dfrac{1}{2}\dfrac{mr^2}{2}(\dfrac{v}{r})^2$

$K'=\dfrac{1}{4}mv^2$

$K'=\dfrac{1}{4}\times 1\times 3^2$

K' = 2.25 J

Hence, this is the required solution.

5 0

3 years ago

A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, $\Delta t=0.003\ s$

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

$F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N$

So, the average force on ball by the golf club is 340 N.

4 0

4 years ago

Derive an algebraic equation for the vertical force that the bench exerts on the book at the lowest point of the circular path i

fiasKO [112]

Answer:

The algebraic equation is:

$F_{v} =\frac{m_{b}v_{b}^{2} }{R} -m_{b} g$

Explanation:

Given information:

mb = book's mass

vb = tangential speed

R = radius of the path

Question: Derive an algebraic equation for the vertical force, Fv = ?

To derive the equation, we need to draw a force diagram for this case, please, see the attached diagram. As you can see, there are three types of forces acting on the system. Two up and one of the weight acting down. Therefore, the algebraic equation is as follows:

$F_{v} =\frac{m_{b}v_{b}^{2} }{R} -m_{b} g$

The variables were defined above and g is the gravity.