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emmainna [20.7K]
2 years ago
13

Weight of 9.81 N calculate its mass??

Physics
1 answer:
Fudgin [204]2 years ago
6 0

Answer:

0.981kg

Explanation:

As we know,

1kg =10N

So,

mass = 9.81/10 = 0.981Kg

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John runs around a 126.5 m circular track 3.5 times in 4.17 minutes. What is his average speed?
sdas [7]
Average speed = distance traveled / time

average speed  = (126.5 m * 3.5 laps) / (4.17 min)

= 106.2 m/min
6 0
3 years ago
One of the most efficient engines built so far has the following characteristics: combustion chamber temperature = 1900°C, exhau
suter [353]

Answer:

actual efficiency is  47.78 %

Carnot efficiency  is 67.65 %

power output is 5.20 × 10^3 hp

Explanation:

given data

temperature = 1900°C = 1900+ 273 K = 2173 K

exhaust temperature = 430°C = 430 + 273 K = 703 K

fuel = 7.0 × 10^9 cal

work = 1.4 × 10^10 J

to find out

actual efficiency  and Carnot efficiency and power output of engine

solution

first we find actual efficiency that is = work / heat input

put the value and

input energy  = 7.0 × 10^9 cal  (4.184 J/1 cal)  = 29.29 × 10^9 J

actual efficiency  =  1.4 × 10^10 / ( 29.29 × 10^9 )

actual efficiency  =  0.4778

actual efficiency is  47.78 %

and

Carnot efficiency  is = 1 - ( 703 / 2173 )

so Carnot efficiency  is  = 0.67648

Carnot efficiency  is 67.65 %

and

power output  = work / time

power output  =  1.4 × 10^10 / 3600 sec

power output = 3.88 × 10^6 W

power output = 3.88 × 10^6 W / 746 hp

so power output is 5.20 × 10^3 hp

5 0
3 years ago
If a kestrel eats a mouse that eats grass the kestrel is a
vovangra [49]
<span> Second-level consumer </span>
5 0
3 years ago
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For the circuit in the previous part, with the frequency set at 1 hz, what happens if the inductance of the inductor is increase
lubasha [3.4K]
The relationship between inductance and frequency can be clearly described using the following equation of inductive reactance:

Xl = 2*pi*f*L ; simplifying:

L = Xl / 2*pi*f

Therefore, as what we saw, inductance and frequency are inversely proportional. To add up, when inductance increases the frequency would decrease.
7 0
3 years ago
A real power supply can be modeled as an ideal EMF of 60 Volts in series with an internal resistance. The voltage across the ter
lara31 [8.8K]

Answer:

5 ohms

Explanation:

Given:

EMF of the ideal battery (E) = 60 V

Voltage across the terminals of the battery (V) = 40 V

Current across the terminals (I) = 4 A

Let the internal resistance be 'r'.

Now, we know that, the voltage drop in the battery is given as:

V_d=Ir

Therefore, the voltage across the terminals of the battery is given as:

V= E-V_d\\\\V=E-Ir

Now, rewriting in terms of 'r', we get:

Ir=E-V\\\\r=\frac{E-V}{I}

Plug in the given values and solve for 'r'. This gives,

r=\frac{60-40}{4}\\\\r=\frac{20}{4}\\\\r=5\ ohms

Therefore, the internal resistance of the battery is 5 ohms.

5 0
3 years ago
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