Answer:
m= 10 kg a = 52 m / s²
Explanation:
For this problem we must use Newton's second law, let's apply it to each axis
X axis
F - fr = ma
The equation for the force of friction is
-fr = miu N
Axis y
N- W = 0
N = mg
Let's replace and calculate laceration
F - miu (mg) = ma
a = F / m - mi g
a = 527.018 / m - 0.17 9.8
We must know the mass of the body suppose m = 10 kg
a = 527.018 / 10 - 1,666
a = 52 m / s²
1 volt is the difference in potential that 1 coulomb of charge requires 1 joule of energy
in order to cross, or gives up 1 joule of energy in crossing, depending on the sign of the
charge and whether it climbs or falls through the 1 volt.
1 volt = 1 joule per coulomb
B) The amount of work done
Answer:
4213.2 Km/h
Explanation:
Given:
Initial Speed of space vehicle relative to Earth, u = 4150 km/h
Mass of rocket motor = 4m
speed of the rocket motor relative to command module , v' = 79 Km/h
Mass of the command module = m
Now,
let the speed of command module relative to earth be 'v'
From the conservation of momentum, we have
( 4m + m ) × u = m × v + (4m × (v - v'))
or
5m × 4150 = mv + 4mv - 4mv'
or
20750 = 5v - ( 4 × 79 )
or
20750 = 5v - 316
or
v = 4213.2 Km/h