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In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. Having no direction, it is a scalarquantity. In the International System of Units, the unit of power is the joule per second (J/s), known as the watt in honour of James Watt, the eighteenth-century developer of the condenser steam engine. Another common and traditional measure is horsepower (comparing to the power of a horse). Being the rate of work, the equation for power can be written:
Power
Common symbols
Derivations from
other quantities
P = E/t
P = F·v
P = V·I
P = T·ω
As a physical concept, power requires both a change in the physical system and a specified time in which the change occurs. This is distinct from the concept of work, which is only measured in terms of a net change in the state of the physical system. The same amount of work is done when carrying a load up a flight of stairs whether the person carrying it walks or runs, but more power is needed for running because the work is done in a shorter amount of time.
Answer:
1.13 x 10⁵N
Explanation:
Given parameters:
Pressure of the coin press = 3.2 x 10⁸ Pa
radius of the nickel coin = 0.0106m
Unknown:
Force of the press on coil = ?
Solution:
Our knowledge of pressure will help us solve this problem.
Pressure is defined as the force applied per unit area on a body.
Pressure = 
Force = Pressure x Area
Since the pressure is known;
Area of the coin = Area of a circle = π r²
where r is the radius of the coin;
Area of the coin = π x 0.0106² = 3.53 x 10⁻⁴m²
Force = 3.2 x 10⁸ x 3.53 x 10⁻⁴ = 1.13 x 10⁵N
I think it 32, but i’m not sure
Answer:
Final mass=0.89kg
Final pressure=5.6bar
Explanation:
To find mass,m=v/v1
But v1=vf + x(vg-vf)
Vf= 0.001093m^3/kg
Vg= 0.3748m^3/kg
V1= 0.001093+0.5(0.3748-0.001093)
V1= 0.225m^3/kg
M= 0.20/0.225 =0.89kg
Final pressure will be:
V/V1= P/P1
Cross multiply
VP1=V1P
P1= 0.225×5/0.2
P1=:5.6 bar
