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murzikaleks [220]
3 years ago
9

The reason you want the mass of your car to be

Physics
2 answers:
navik [9.2K]3 years ago
6 0

Answer:

God

Explanation:

Jesus

insens350 [35]3 years ago
5 0

Answer:

The initial momentum is 20 kg*m/s and the stopping force is 2 newtons.]\

Explanation:

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How many hour are required to make a 3000 km trip if your average speed is 50 km/h?
lesya692 [45]
That would be 60 hours. 
8 0
3 years ago
A father racing his son has half the kinetic energy of the son, who has half the mass of the father.The father speeds up by 1.0
Helga [31]

Answer:

(a) v_f=2.414\ m.s^{-1}

(b) v_s=4.828\ m.s^{-1}

Explanation:

Let:

mass of father be, m_f

mass of son be, m_s=\frac{m_f}{2}

speed of son be, v_s

initial speed of father be, v_f

After speeding up, speed of father is  v_f+1

<u>We know Kinetic Energy is given as</u>

KE=\frac{1}{2} m.v^2 .....................................(1)

where:

m = mass

v = velocity

Hence, according to the initial condition the father is having kinetic energy half the kinetic energy of the son.

KE_s=2.KE_f

\frac{1}{2} m_s.v_s^2=2\times \frac{1}{2} m_f.v_f^2

(\frac{m_f}{2})\times v_s^2=2\times m_f\times v_f^2

v_s=2v_f .................................................(2)

According to the final condition:

\frac{1}{2} m_s.v_s^2= \frac{1}{2} m_f.(v_f+1)^2

(\frac{m_f}{2})\times v_s^2=m_f.(v_f+1)^2

v_s^2=2(v_f+1)^2

v_s=\sqrt{2}(v_f+1).....................................................(3)

(a)

From eq. 2 & 3

2v_f=\sqrt{2}(v_f+1)

\sqrt{2}\ v_f=(v_f+1)

v_f(\sqrt{2}-1)=1

v_f=\frac{1}{(\sqrt{2}-1)}

v_f=2.414\ m.s^{-1}

(b)

<em>putting the above value in eq. (2)</em>

v_s=4.828\ m.s^{-1}

4 0
4 years ago
Jack and Jill have a pail of water. Which action will cause the molecules of water to move faster?
Tcecarenko [31]
Heating up the water.
7 0
4 years ago
Read 2 more answers
When electrons are accelerated by 2450 V in an electron microscope, they will have
Anni [7]
I think the answer to this is 0.811nm
5 0
3 years ago
Sherlock Holmes examines a clue by holding his magnifying glass (with
Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

M=-\frac{q}{p}=-\frac{-30}{10}=3

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

8 0
4 years ago
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