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damaskus [11]
3 years ago
15

3. What is the difference between the law of gravity and the theory of gravity?_________________________________________________

_______________________________________________
Physics
1 answer:
Phoenix [80]3 years ago
7 0

Answer:-

In physics a law describes a natural phenomenon, but does not attempt to describe how it works.

Newton's law of gravitation describes the attractive force F between two bodies with masses m1 and m2, which are a distance r apart.

f = gm_1m_2/r²

Where G is the gravitational constant.

This is a law because it describes the force but makes not attempt to explain how the force works.

A theory is an explanation of a natural phenomenon. Einstein's General Theory of Relativity explains how gravity works by describing gravity as the effect of curvature of four dimensional spacetime.

Einstein also produced an equation which describes gravity. It may look simple, but in reality it is very complex and very hard to solve.

Gμν=\frac{8\pi \: g}{ {c}^{2} } tμν

So, we have both a law and a theory of gravity.

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The state of strain at a point is plane strain with εx = ε0, εy = –2ε0, γxy = 0, where ε0 is a positive constant. What is the no
Marat540 [252]

Answer:

The normal strain along an axis oriented 45° from the positive x axis in the clockwise direction is -ε₀/2

Explanation:

Given that

\epsilon_{x}=\epsilon_{o}\\\\\epsilon_{y}=-2\epsilon_{o}\\\\\gamma_{xy}=0\\\\\theta=-45^{o}\\\\\epsilon_{x_{1}}=?

From equation of normal strain in x direction:

\epsilon_{x_{1}}=\epsilon_{x}cos^{2}\theta+\epsilon_{y}sin^{2}\theta+\gamma_{xy{ sin\theta cos\theta

Substituting the values:

\epsilon_{x_{1}}=\epsilon_{o}cos^{2}(-45)-2\epsilon_{o}sin^{2}(-45)+0\\\\\epsilon_{x_{1}}=\frac{\epsilon_{o}}{2}-2\frac{\epsilon_{o}}{2}\\\\\epsilon_{x_{1}}=-\frac{\epsilon_{o}}{2}

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2 years ago
One heater uses 310 W of power when connected by itself to a battery. Another heater uses 180 W of power when connected by itsel
igor_vitrenko [27]

Answer:

55.8W

Explanation:

P= V^2/R

R= V^2/P

For series connection

Req= R1+ R2= V^2/310 + V^2/180

R=V^2/P= V^2/310 + V^2/180

But V^2 will cancel out

P= 1/(1/310 + 1/180)

P= 55.8W

8 0
2 years ago
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What is the difference between 3.15 m and 2.006 m with the correct number of significant figures
snow_lady [41]
The differences is 1.144
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Pressure can affect the density of<br><br> Solids<br> Liquids<br> Gases<br> Metals
gtnhenbr [62]

Answer;

-Gases

Explanation;

-Pressure can affect the density of gases.

-Density of gases changes with pressure and temperature because gases are compressible fluid and because they are compressible, when pressure increases molecules come closer to each other which means increase in density and when pressure drops molecules of gases become free to expand and get away from each other which density decrease.

7 0
3 years ago
I attach a 4.1 kg block to a spring that obeys Hooke's law and supply 3.8 J of energy to stretch the spring. I release the block
borishaifa [10]

Answer:

The amplitude of the oscillation is 2.82 cm

Explanation:

Given;

mass of attached block, m = 4.1 kg

energy of the stretched spring, E = 3.8 J

period of oscillation, T = 0.13 s

First, determine the spring constant, k;

T = 2\pi \sqrt{\frac{m}{k} }

where;

T is the period oscillation

m is mass of the spring

k is the spring constant

T = 2\pi \sqrt{\frac{m}{k} } \\\\k = \frac{m*4\pi ^2}{T^2} \\\\k = \frac{4.1*4*(3.142^2)}{(0.13^2)} \\\\k = 9580.088 \ N/m\\\\

Now, determine the amplitude of oscillation, A;

E = \frac{1}{2} kA^2

where;

E is the energy of the spring

k is the spring constant

A is the amplitude of the oscillation

E = \frac{1}{2} kA^2\\\\2E = kA^2\\\\A^2 = \frac{2E}{k} \\\\A = \sqrt{\frac{2E}{k} } \\\\A =  \sqrt{\frac{2*3.8}{9580.088} }\\\\A = 0.0282 \ m\\\\A = 2.82 \ cm

Therefore, the amplitude of the oscillation is 2.82 cm

8 0
2 years ago
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