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3 years ago

5

A circuit has a current of 1.2 A. If the voltage decreases to one-third of its original amount while the resistance remains cons

tant, what will be the reaulting current?

1 answer:

rosijanka [135]3 years ago

6 0

Answer:

1.2*1/3

Explanation:

Multiply the current by the volatage to get ur ans

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The magnitude of a force vector is 89.6 newtons (N). The x component of this vector is directed along the +x axis and has a magn

insens350 [35]

Answer:

(a) θ = 33.86°

(b) Ay = 49.92 N

Explanation:

You have that the magnitude of a vector is A = 89.6 N

The x component of such a vector is Ax = 74.4 N

(a) To find the angle between the vector and the x axis you use the following formula for the calculation of the x component of a vector:

$A_x=Acos\theta$ (1)

Ax: x component of vector A

A: magnitude of vector A

θ: angle between vector A and the x axis

You solve the equation (1) for θ, by using the inverse of cosine function:

$\theta=cos^{-1}(\frac{A_x}{A})=cos{-1}(\frac{74.4N}{89.6N})\\\\\theta=33.86\°$

the angle between the A vector and the x axis is 33.86°

(b) The y component of the vector is given by:

$A_y=Asin\theta\\\\A_y=(89.6N)sin(33.86\°)=49.92N$

the y comonent of the vecor is Ay = 49.92 N

3 0

2 years ago

A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is

Veronika [31]

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

$F_c = W-N$

$m\omega^2r = W-N$

Here,

m = Net mass

$\omega$ = Angular velocity

r = Radius

W = Weight

N = Normal Force

$m\omega^2r = 174-146$

The net mass is equivalent to

$F = mg \rightarrow m = \frac{F}{g}$

Then,

$m = \frac{174lb}{32.17ft/s^2}$

Replacing we have then,

$(\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb$

Solving to find the angular velocity we have,

$\omega = 0.309rad/s$

Therefore the angular velocity is 0.309rad/s

6 0

2 years ago

In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 50

dem82 [27]

Answer:

$0.1$ m

Explanation:

$d$ = slit width = 0.1 mm = 0.1 x 10⁻³ m

$\lambda$ = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

$D$ = Distance of the screen = 10 m

$w$ = Spacing between successive minima

Spacing between successive minima is given as

$w = \frac{2D\lambda }{d}$

Inserting the values given

$w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}$

$w = 0.1$ m

4 0

3 years ago

A soap bubble appears red (λ = 633nm) at the point on its front surface nearest to the viewer. Assuming n = 1.35, what is the sm

alexira [117]

Answer:

The smallest film thickness is 117 nm.

Explanation:

Light interference on thin films can be constructive or destructive. Constructive interference is dependent on the film thickness and the refractive index of the medium.

For the first interference (surface nearest to viewer), the minimum thickness can be expressed as:

$2t_{min} = \frac{wavelenth}{2n}$

where n is the refractive index of the bubble film.

Therefore,

$2t_{min} = \frac{633x10^{-9} }{(2)(1.35)}$

$2t_{min} =2.344x10^{-7}$

∴ $t_{min} =\frac{2.344x10^{-7} }{2}$

$t_{min} = 1.17x10^{-7} m = 117 nm.$

7 0

3 years ago

What is population density?

Tpy6a [65]

Population density<span> (in agriculture: standing stock and standing crop) is a measurement of </span>population<span> per unit area or unit volume; it is a quantity of type number </span>density<span>. It is frequently applied to living organisms, and most of the time to humans.</span>

3 0

3 years ago

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