Answer:
466 km/h
255°
measured anticlockwise from the east direction
Explanation:
find the resultant velocity of a plane after a crosswind affects its motion. take the positive
x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are
- <em>upx =</em> 0
- <em>upy = 450 Km/ h</em>
<em>And for the wind.</em>
- <em>uwx = - 120 Km/h</em>
- <em>uwy = 0</em>
<em>The components for the r</em><em>esultant velocity </em><em>of the plane are given by</em>
- <em>ux =upx + uwx = 0 - 120 Km/h = </em><u><em>- 120 Km/h</em></u>
- <em>uy = upy + uwy = - 450 Km/h +0 = </em><u><em>- 450 Km/h</em></u>
<em>The </em><em>magnitude </em><em>of the resultant velocity is</em>
<em />
= 466 km/h
Hope this helps u : )