<span>The proton differs from the electron in sign although they have the same value. Like the electron, a proton will gain 215 electron-volts of eV in Kinetic energy. So 1.602Ă—10^-19 J * 215 = 344.43 * 10^(-19) J.
But K. E. = mv^2 / 2, so v^2 = 2 * K.E/m. The mass of a proton is 1.673 * 10^-27 kg. So v = âš(2 * 344.43 * 10^(-19))/1.673Ă—10^-27 = 688.86 * 10^(-19)/1.673Ă—10^(-27) = 411.75 * 10^(-19-(-27)) = âš411.75 * 10^(8) = 202196.56
Also for the electron we have v^2 = 2 * K.E/m but here mass, m, = 9.109 * 10^-31 kg. So we have v = âš(2 * 344.43 * 10^(-19)) / 9.109 * 10^-31 = 688.86 * 10^(-19)/ 9.109 * 10^-31 = 75.624 * 10^(-19 - (-31)) = 75.624 * 10^(21) and v = 2.749 * 10^11</span>
Number 19 is frequency and not sure which question you asked!!!??
<span>Flexibility exercises should be done in conjunction with strength-building exercises because:
</span><span>They work together to maintain your overall level of fitness.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Just from that one observation, choice-B
would be a reasonable conclusion.
Answer:
The velocity of the light will be 1.0c only
Explanation:
The velocity of the light measured in the case given in question will be 1.0c only.
This is due to the fact that the velocity of light is never relative. The velocity of the light is maximum
The velocity of the light cannot be scaled down in no case
Thus, the velocity of the light remains as constant.
Hence, the velocity of the light measured will be 1.0c although the ships have relative velocity.
