Answer:
2 m/s^2
Explanation:
a = v^2/r
a = (10m/s)^2 / 50m
a = 2 m/s^2
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A box is sliding up an incline that makes an angle of 14.0° with respect to the horizontal. the coefficient of kinetic friction between the box and the surface of the incline is 0.180. the initial speed of the box at the bottom of the incline is 2.20 m/s. how far does the box travel along the incline before coming to rest?
Answer:
The speed traveled by the car is 40 meter per second.
Explanation:
The formula for the relation between the power and the force is as follows:
P = Fv
Where F is the force and v is the speed.
As given
To travel at constant speed, a car engine provides 24KW of useful power. The driving force on the car is 600N.
F = 600 N
Convert power from KW to W.
1 KW = 1000 W
24 KW = 24 × 1000 W
= 24000 W
Thus
P = 24000 W
Put these values in the formula.
24000 = 600 × v
24000 = 600v

v = 40 meter per second .
Therefore the speed of the car is 40 meter per second .
The Cell Membrane is what controls what enters and leaves the cell.