Answer:
True The grid with more slits gives more angle separation increases
True. The grating with 10 slits produces better-defined (narrower) peaks
Explanation:
Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is
d sin θ = m λ
where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.
For network with 5 slits
d = 1/5 = 0.2
For the network with 10 slits
d = 1/10 = 0.1
let's calculate the separation (teat) for each one
θ = sin⁻¹ (m λ / d)
for 5 slits
θ₅ = sin⁻¹ (m λ 5)
for 10 slits
θ₁₀ = sin⁻¹ (m λ 10)
we can appreciate that for more slits the angle increases
the intensity of a series of slits is
I = I₀ sin²2 (N d/2) / sin² d/2)
when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)
let's analyze the claims
False
True The grid with more slits gives more angle separation increases
False
True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases
False
The "penetration of the bullet" is 5 m
<u>Explanation</u>:
A "bullet" with "kinetic energy" of = 400J
A resistive force stops the bullet = 8.00 x 10 N
Work = change in energy
Work = ∆ Kinetic Energy (equation 1)
Work = 
(equation 2)
From equations 1 and 2 we have,
= ∆ Kinetic Energy
Where
,
Kinetic Energy = 400 J
F = 8.00 x 10 N
(8.00 x 10 N) d = 400 J
(80 N) d = 400 J
d = 5 m
The penetration of the bullet is 5 m
Weight on any planet is (mass) x (acceleration of gravity there).
Acceleration of gravity on Earth is about 9.8 meters per second² .
So weight of 50 kg on Earth is (50 x 9.8) = <u>490 newtons</u>.
(That's about 110.2 pounds.)
Gravity slows the upward speed of any rising object by 9.8 m/s every second.
If the ball is tossed upward at 20 m/s, then it's at the top of its arc and its speed has dwindled to zero in (20/9.8) = 2.04 seconds.
During that time, its starting speed is 20 m/s and its ending speed is zero, so its AVERAGE speed all the way up is (1/2) (20 + 0) = 10 m/s .
Sailing upward for 2.04 seconds at an average speed of 10 m/s, the ball rises to (2.04 x 10) = <em>20.4 meters.</em>
