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Degger [83]
3 years ago
11

Why are special techniques and extinguishing agents are required to fight combustible metals fires?

Physics
1 answer:
d1i1m1o1n [39]3 years ago
7 0
Cucucicicicivigovogovphphpbpb
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Determine the normal boiling point of a substance whose vapor pressure is 55.1 mm hg at 35°c and has a δhvap of 32 .1 kj/mol. de
atroni [7]
Classius claperyon equation
In (P2/ P2) = ΔHvap/R) × (1/T2-1/T1)
T2 occurs at normal boiling when vapor pressure P2 = 1 atm.
P1 = 55.1 mmHg, P2 = 1 atm = 760mmHg
T1 = 35°c = 308.15k, T2 =
ΔHvap = 32.1kJ/mol = 32100 J/mol
In (760/55.1) = (-32100/ 8.314) × ( 1/T2 - 1/308.15)
The normal boiling point T2 = 390k = 117°c
5 0
3 years ago
A non-licensed person may be the SOLE owner of a civil, electrical, or mechanical engineering business under which of the follow
ra1l [238]

Answer:

No.

Explanation:

The "guide to Engineering and land surveying" for professional engineers and land surveyors by the California board reviews that an unlicensed person cannot be a sole owner of an engineering business, unless there is partnership with a licensed engineer.

4 0
3 years ago
Read 2 more answers
Please help me please please, i will brainliest the right answer
konstantin123 [22]
Help with whatttt? there’s nothing
3 0
2 years ago
A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0
defon

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

1)

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

I=\frac{q}{t}

where

I is the current

q is the amount of charge passing a given point in a time t

For the wire in this problem, we have

q = 9.0 C is the amount of charge

t = 2.0 s is the time interval

Solving for I, we find the current:

I=\frac{9.0}{2.0}=4.5 A

2)

To solve this problem, we can use again the same formula

I=\frac{q}{t}

where

I is the current

q is the amount of charge passing a given point in a time t

In this problem, we have:

I = 3.0 A (current)

q = 14.0 C (charge)

Therefore, the time taken for the charge to move past a particular spot in the wire is

t=\frac{q}{I}=\frac{14.0}{3.0}=4.7 s

Learn more about electric current:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

8 0
3 years ago
What kind of energy does an unlit match have?
Oliga [24]

The type of energy that an unlit match has is potential energy.

5 0
2 years ago
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