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nexus9112 [7]
2 years ago
12

What is the amount of energy (in kJ) released when 1 mole of photons are emitted from an electron transition of n

Chemistry
1 answer:
pychu [463]2 years ago
3 0

Explanation:

The formula applied here is rydberg's equation (Bohr's equation.)

E = -Rh (1/(nf)^2 - 1/(ni)^2)

where Rh = Rydberg constant = 2.8*10^-18

1 mole = 6.02 * 10^23 particles

nf & ni stand for final & initial principal quantum numbers respectively.

your question lacks the principal quantum numbers.

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<span>A compound is found to be 40.0% carbon, 6.7% hydrogen and 53.5% oxygen. Its molecular mass is 60. g/mol. 
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Empirical formula is the simplest ratio of whole numbers of components making up a compound.
the percentages have been given, therefore we can calculate for 100 g of the compound.

                                C                            H                        O
Mass in 100 g      40.0 g                       6.7 g                   53.5 g
Molar mass            12 g/mol                1 g/mol                 16 g/mol
Number of moles   40.0/12= 3.33         6.7/1 = 6.7          53.5/16 = 3.34
Divide by the least number of moles  
                             3.33/3.33 = 1           6.7/3.33 = 2.01   3.34/3.33 = 1.00
after rounding off
C - 1 
H - 2
O - 1

Empirical formula - CH₂O

Q2)
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Mass of one mole of compound = 60 g
Number of empirical units = 60 g / 30 g = 2
Therefore molecular formula - 2(CH₂O) 
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