Answer:
A liquid, at any temperature, is in equilibrium with its own steam. This means that on the surface of the liquid or solid substance, there are gaseous molecules of this substance. These molecules exert a pressure on the liquid phase, a pressure known as vapor pressure.
In chemistry, when we talk about dry basis, we talk about a state in which the presence of water in a gaseous state is denied for the calculation. So vapor pressure equals zero.
When we talk about the wet basis, the presence of water in the steam is considered for the calculation, which normally is expressed as a percentage or moisture.
In summary, for a gas mixture steam:
- For dry basis, we just have <em>component A, component B....</em>
- For wet basis, we have <em>water vapor, component A, component B...</em>
So, in wet basis we have an extra component (water).
Assuming we only have 2 components in our steam, and being X the molar fraction of eact component:
- For dry basis: Xa + Xb = 1................................. Xa = 1 - Xb
- For wet basis: Xa + Xb + Xwater = 1 .............Xa = 1 - Xwater - Xb
For dry basis the mole fraction of A it is obtained by subtracting the molar fraction of B from one. And for wet basis, we have to substract the molar fraction of B <u>AND </u>the molar fraction of water vapor. So, logically, the mole fraction Xa will be less for wet basis.
Answer:
0.016 m³
Explanation:
Step 1: Given data
Width of the tank (w): 18 in
Height of the tank (h): 11 in
Depth of the tank (d): 5 in
Step 2: Calculate the volume of the tank in in³
The fuel tank is a cuboid. We can calculate its volume using the following expression.
V = w × h × d
V = 18 in × 11 in × 5 in
V = 990 in³
Step 3: Convert 990 in³ to m³
We will use the relationship 1 m³ = 61023.7 in³.
990 in³ × (1 m³ / 61023.7 in³) = 0.016 m³
Answer:
Compound A: 1-bromo-1-methylcyclohexane
Compound B: 1-methylcyclohex-1-ene
Explanation:
In this question, we can start with the <u>I.D.H</u> (<em>hydrogen deficiency index</em>):
In the formula we have 7 carbons, 13 hydrogens, and 1 Br, so:
We have an <u>I.D.H value of one</u>. This indicates that we can have a <u>cyclic structure or a double bond</u>.
We have to keep in mind that the Br atom must be bonded to a t<u>ertiary carbon</u>. <u>We can not have a double bond</u> because in the ozonolysis reaction we have only <u>1 product</u>, therefore, we can not have a double bond in the initial molecule (if we have a double bond in the initial molecule we will have more than 1 product in the ozonolysis reaction).
With this in mind, we will have a <u>cyclic structure</u>. If we have 7 carbons and we need a tertiary alkyl halide. We can have a cyclic structure of 6 members and a methyl group bonded to a carbon that also is bonded to a Br atom <u>(1-bromo-1-methylcyclohexane).</u>
In the reaction with 
we will have an <u>elimination reaction</u>. In other words, we have the production of a double bond inside of the cyclic structure <u>(1-methylcyclohex-1-ene)</u>.
See figure 1 for further explanations.
I hope it helps!
By hot springs, fumaroles and geysers.
Presence of Oxygen in mitochondria is called Aerobic conditions and under this aerobic conditions Pyruvic acid is converted into Acetyl Co.A which enters Krebs' cycle
while in absence of oxygen which called Anaerobic conditions pyruvic acid is converted into Lactic acid to avoid accumulation of NADH⁺ which inhibit glycolysis and provide NAD⁺ required for glycolysis
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