Answer:
2.445 g
Explanation:
Step 1: Given and required data
- Energy in the form of heat required to boil the water (Q): 5525 J
- Latent heat of vaporization of water (∆H°vap): 2260 J/g
Step 2: Calculate the mass of water
We will use the following expression.
Q = ∆H°vap × m
m = Q / ∆H°vap
m = 5525 J / (2260 J/g)
m = 2.445 g
Answer:
D
Explanation:
pH=-log(x)
x=0.001M,pH=3
x=0.01M,pH=2
x=0.1M,pH=1
x=1M,pH=0
Highest pH is for option D
