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arsen [322]
3 years ago
14

Consider a carbon atom that is sp hybridized. Indicate how many of each orbital exist on this carbon atom by sorting each orbita

l type. Consider the outer valence only.
Options include: sp orbitals, p orbitals, s orbitals

Put them in the following categories:

Zero One Two Three

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Explanation:

It is known that atomic number of carbon is 6 and its electronic configuration is 1s^{2}2s^{2}2p^{2}. This means that in its neutral state it contains 2 electrons in its s-orbital and 2 electrons in its p-orbital.

After excitation there will be one electron present in its s-orbital and three electrons present in p-orbital.

Therefore, after the hybridization there will be in total 2 sp hybrid orbitals, 2 p-orbitals and zero s-orbital.

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DiKsa [7]

subatomic particles are measured using amu (atomic mass unit)

<em>hope this helps!</em>

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7 0
3 years ago
How many molecules are present in each sample?8.55 mol SO2 :molecules SO2 0.603 mol CO :molecules CO a sample of NH3 containing
sineoko [7]

Answer:

- 5.15×10²⁴ molecules of sulfur dioxide

- 3.63×10²³ molecules of carbon monoxide

- 6.02×10²³ molecules of ammonia

Explanation:

We begin from the relation that 1 mol of molecules contains NA of molecules

NA = 6.02×10²³

Now, we make rules of three:

1 mol has 6.02×10²³ molecules, therefore:

8.55 moles of SO₂ must have (8.55 . NA) / 1 = 5.15×10²⁴ molecules of dioxide

0.603 moles of CO must have (0.603 . NA) / 1 = 3.63×10²³ molecules of monoxide

Avogadro's Number of molecules of NH₃ are 6.02×10²³ molecules of ammonia

3 0
2 years ago
1
Molodets [167]

Answer: The temperature does effect the growth of the plants. If you kept them all at different temperature and the growth was different then the temperature is definitly a factor in plant growth

Explanation:

7 0
3 years ago
A student prepares a aqueous solution of butanoic acid . Calculate the fraction of butanoic acid that is in the dissociated form
ella [17]

Answer:

15.4%

Explanation:

If Ka = 0.54 mM = 1.51x10⁻⁵

Then;

C₄H₈O₂               -------->            C₄H₇O₂⁻          +           H⁺

I                    0.54x10⁻³                             0                                0

E                   0.54x10⁻³(1-x)                      0.54x10⁻³x                0.54x10⁻³x

Recall that x is the percentage degree of dissociation

From the ICE table;

Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]

1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)  

1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x

1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2

1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2

Hence;

0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0

x^2 + 0.028x - 0.028 = 0

Solving the quadratic equation here;

x = 0.154 or −0.182

Ignoring the negative result, x = 0.154

Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%

3 0
2 years ago
Which of the following is a characteristic of a mixture? Definite composition Each substance in the mixture retains its own prop
Butoxors [25]
A mixture can be separated a solution cannot
7 0
3 years ago
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