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3 years ago

Which element have the same lewis dot structure as silicon ?

2 answers:

4 0

You just look at what vertical row that silicon is, and every element that is in the same vertical row as silicon will have the same lewis dot structure...and this applyes for most elements on the periodic table of elements.
- C, Ge,Sn, Pb:
all these elements are in the same column, and therefore have the same number of valence electrons

Makovka662 [10]3 years ago

4 0

Answer:

Carbon (C), Germanium (Ge), Tin (Sn), Lead (Pb), and Flerovium (Fl)

Explanation:

Silicon is the element of fourteenth group and third period. The electronic configuration of Silicon is - 2, 8, 4 or $1s^22s^22p^63s^23p^2$

There are 4 valence electrons of silicon.

Only the valence electrons are shown by dots in the Lewis structure.

As, stated above, there are four valence electrons of silicon, so in the Lewis structure, four dots are made around the silicon (Si) symbol.

Similarly, the other members of the group 14 have four valence electrons and will have same valence electrons as silicon.

<u>So, the elements are:- Carbon (C), Germanium (Ge), Tin (Sn), Lead (Pb), and Flerovium (Fl)</u>

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Which of the following metals reacts with aqueous Cubo A) Au B) Ag C) Hg D) all of the above E) none of the above

Yanka [14]

Answer:

E) None of the above

Explanation:

Metals react according to the activity series, thta is organized with the leats metals in in the bottom and the most reactive metals in the top. Most reactive metals displace less reactive metals in the compounds they are found.

in this series, Gold, Silver and Mercury are below Copper, this is, they are less reactive than Cu. this means none of them can displace it from its compounds.

4 0

3 years ago

The chemical reaction involving an acid and a base or alkali is know as a

saul85 [17]

Ans

Neutralization reaction

Explanation:

The meaning is

acid + base = salt + water

5 0

3 years ago

Read 2 more answers

A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3

ELEN [110]

Answer:

The volume of the gas sample at standard pressure is <u>819.5ml</u>

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

$V_1=250ml$

$V_2=?$

$P_{total}=735 mmhg$

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

$P_{water}=42.2mmhg$

$T_1=35°C=35+273=308 K$

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

$P_{gas}=P_{total}-P_{water}$

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

$\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}$

$V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1$

$V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1$

Here $P_2 \:and\: T_2$ are standard pressure and temperature respectively.

we have

$P_2=750mmhg \:and\: T_2=273K$

Substituting value, we get

$V_2=\frac{692.8}{750}*\frac{273}{308} *250$

$V_2= 819.51 ml$

4 0

2 years ago

Does the amount of methanol increase, decrease, or remain the same when an equilibrium mixture of reactants and products is subj

denis23 [38]

Answer:

a. Methanol remains the same

b. Methanol decreases

c. Methanol increases

d. Methanol remains the same

e. Methanol increases

Explanation:

Methanol is produced by the reaction of carbon monoxide and hydrogen in the presence of a catalyst as follows; 2H2+CO→CH3OH.

a) The presence or absence of a catalyst makes no difference on the equilibrium position of the system hence the methanol remains constant.

b) The amount of methanol decreases because the equilibrium position shifts towards the left and more reactants are formed since the reaction is exothermic.

c) If the volume is decreased, there will be more methanol in the system because the equilibrium position will shift towards the right hand side.

d) Addition of helium gas has no effect on the equilibrium position since it does not participate in the reaction system.

e) if more CO is added the amount of methanol increases since the equilibrium position will shift towards the right hand side.

3 0

3 years ago

If you have 5.42 x 1024 aluminum atoms, approximately how many moles is that

sattari [20]

Answer:

<h2>9.00 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.42 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 9.0033$

We have the final answer as

<h3>9.00 moles</h3>

Hope this helps you

4 0

3 years ago