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kap26 [50]
3 years ago
10

Which element have the same lewis dot structure as silicon ?

Chemistry
2 answers:
ExtremeBDS [4]3 years ago
4 0
You just look at what vertical row that silicon is, and every element that is in the same vertical row as silicon will have the same lewis dot structure...and this applyes for most elements on the periodic table of elements.                        
 - C, Ge,Sn, Pb:                                                                                                  
all these elements are in the same column, and therefore have the same number of valence electrons
Makovka662 [10]3 years ago
4 0

Answer:

Carbon (C), Germanium (Ge), Tin (Sn), Lead (Pb), and Flerovium (Fl)

Explanation:

Silicon is the element of fourteenth group and third period. The electronic configuration of Silicon is - 2, 8, 4 or 1s^22s^22p^63s^23p^2

There are 4 valence electrons of silicon.

Only the valence electrons are shown by dots in the Lewis structure.  

As, stated above, there are four valence electrons of silicon, so in the Lewis structure, four dots are made around the silicon (Si) symbol.

Similarly, the other members of the group 14 have four valence electrons and will have same valence electrons as silicon.

<u>So, the elements are:- Carbon (C), Germanium (Ge), Tin (Sn), Lead (Pb), and Flerovium (Fl)</u>

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Compare and contrast a pure substance with a mixture and give an example.
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What is the oxidation state of Hg in Hg2Cl2?​
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Answer:

+1

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5 0
3 years ago
Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = 165°C

Depression in freezing point = \Delta T_f=?

\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

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The molality of isoborneol in camphor is 0.53 mol/kg.

8 0
3 years ago
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