1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Romashka-Z-Leto [24]
3 years ago
9

How does adding oxygen (O2) to this reaction change the equilibrium? 2SO2(g) + O2(g) ⇌ 2SO3(g) A. The equilibrium shifts right t

o produce more SO3 molecules. B. The equilibrium shifts left to produce more O2 molecules. C. The equilibrium shifts right because of decreased collisions between SO2 and O2 molecules. D. The equilibrium shifts left with an increase in SO2 and O2 molecules. E. The equilibrium shifts left because of increased collisions between SO2 and O2 molecules.
Chemistry
1 answer:
liq [111]3 years ago
8 0

The equilibrium law or the Le Chatelier's principle states that when a system encounters a disturbance like a temperature, concentration, or pressure modifications, it will react to restore a new state of equilibrium.  

In the given case, adding reactant, that is, oxygen will shift the reaction in the direction of the product, on the basis of Le Chatelier's principle. Thus, the equilibrium will move toward the product side. So, the correct answer will be option A, that is, the equilibrium shifts right to produce more SO₃ molecules.  


You might be interested in
1) A certain compound has an empirical formula of CH_6O_ 2. Its molar mass is between 285 and 315 g/mol. What is its molecular f
KIM [24]

1. The molecular formula of the compound is C₆H₃₆O₁₂

2. The molecular formula of the compound is N₂H₄O₂

3 The empirical formula and molecular formula of the compound are: C₂H₃ and C₄H₆

4. The empirical formula of the compound is C₃H₆O

5. The empirical formula of the compound is ZrSiO₄

<h3>1. How to determine the molecular formula </h3>
  • Empirical formula = CH₆O₂
  • Molar mass = (285 + 315) / 2 = 600 / 2 = 300 g/mole
  • Molecular formula =?

Molecular formula = empirical × n = molar mass

[CH₆O₂]ₙ = 300

[12 + (6×1) + (16×2)]ₙ = 300

50n = 300

Divide both side by 74

n = 300 / 50

n = 6

Molecular formula = [CH₆O₂]ₙ

Molecular formula = [CH₆O₂]₆

Molecular formula = C₆H₃₆O₁₂

<h3>2. How to determine the molecular formula </h3>
  • Empirical formula = NH₂O
  • Molar mass = (55 + 65) / 2 = 120 / 2 = 60 g/mole
  • Molecular formula =?

Molecular formula = empirical × n = molar mass

[NH₂O]ₙ = 60

[14 + (2×1) + 16]ₙ = 60

32n = 60

Divide both side by 32

n = 60 / 32

n = 2

Molecular formula = [NH₂O]ₙ

Molecular formula = [NH₂O]₂

Molecular formula = N₂H₄O₂

<h3>3. How to determine the empirical formula and molecular formula</h3>

We'll begin by obtaining the empirical formula. This is illustrated below:

  • Carbon (C) = 88.9%
  • Hydrogen (H) = 11.1%
  • Empirical formula =?

Divide by their molar mass

C = 88.9 / 12 = 7.4

H = 11.1 / 1 = 11.1

Divide by the smallest

C = 7.4 / 7.4 = 1

H = 11.1 / 7.4 = 3/2

Multiply by 2 to express in whole number

C = 1 × 2 = 2

H = 3/2 × 2 = 3

Thus, the empirical formula of the compound is C₂H₃

Finally, we shall determine the molecular formula of the compound. This is illustrated below:

  • Molar mass of compound = 54 g/mol
  • Empirical formula = C₂H₃
  • Molecular formula =?

Molecular formula = empirical × n = molar mass

[C₂H₃]ₙ = 75.16

[(12×2) + (3×1)]ₙ = 54

27n = 54

Divide both side by 27

n = 54 / 27

n = 2

Molecular formula = [C₂H₃]ₙ

Molecular formula = [C₂H₃]₂

Molecular formula = C₄H₆

<h3>4. How to determine the empirical formula</h3>
  • Carbon (C) = 62.07%
  • Hydrogen (H) = 10.34%
  • Oxygen (O) = 27.59%
  • Empirical formula =?

Divide by their molar mass

C = 62.07 / 12 = 5.1725

H = 10.34 / 1 = 10.34

O = 27.59 / 16 = 1.724

Divide by the smallest

C = 5.1725 / 1.724 = 3

H = 10.34 / 1.724 = 6

O = 1.724 / 1.724 = 1

Thus, the empirical formula of the compound is C₃H₆O

<h3>5. How to determine the empirical formula</h3>
  • Zr = 49.76%
  • Si = 15.32%
  • O = 34.91%
  • Empirical formula =?

Divide by their molar mass

Zr = 49.76 / 91 = 0.547

Si = 15.32 / 28 = 0.547

O = 34.91 / 16 = 2.182

Divide by the smallest

Zr = 0.547 / 0.547 = 1

Si = 0.547 / 0.547 = 1

O = 2.182 / 0.547 = 4

Thus, the empirical formula of the compound is ZrSiO₄

Learn more about empirical and molecular formula:

brainly.com/question/24297883

#SPJ1

7 0
2 years ago
Phosphorus pentachloride decomposes at higher temperatures. PCl5(g) ⇄ PCl3(g) + Cl2(g) An equilibrium mixture at some temperatur
aliya0001 [1]

Answer:

The reaction shifts from right to left. The new concentration of PCl₅ in equilibrium is 1.133 M.

Explanation:

The stress applied to the system is the addition of Cl₂. To offset this  stress, <u>some Cl₂ reacts with PCl₃ to produce PCl₅ until a new equilibrium is established</u>.

The net reaction therefore shifts from right to left, that is,

PCl₅ (g) ← PCl₃ (g) + Cl₂ (g)

To work with the Kc expression, we need to convert the grams to moles. Since the volume of the flask is 1 liter, the moles can be expressed as molarity.

For PCl₅:

208.23 g ---------- 1 mol

3.74 g -------------- x= 1.80 x10⁻² mol ⇒ 1.80 x10⁻² M

For PCl₃:

137.33 g ---------- 1 mol

4.86 g ------------- x= 3.54 x10⁻² mol ⇒ 3.54 x10⁻² M

For Cl₂:

70.91 g ---------- 1 mol

3.59 g ----------- x= 5.06 x10⁻² mol ⇒ 5.06 x10⁻² M

Now, taking into account the shift of the equation, we make an ICE chart:

                   PCl₅ (g)       ←            PCl₃ (g) +                           Cl₂ (g)

i)             1.80 x10⁻²                   3.54 x10⁻²                           5.06 x10⁻²

c)                   +x                                 -x                             +1.31 x10⁻² -x

e)           1.80 x10⁻² +x           3.54 x10⁻² -x             5.06 x10⁻²+1.31 x10⁻² -x

Now, we write the Kc formula:

Kc = [PCl₃] [Cl₂] / [PCl₅]

Kc = [ 3.54 x10⁻² -x] [5.06 x10⁻²+1.31 x10⁻² -x] / [1.80 x10⁻² +x]

After working with the expression, we find that x = 1.115.

Therefore, the new concentration of  PCl₅ will be 1.133 M.

7 0
3 years ago
Read 2 more answers
In terms of shape and volume, how can a gas be defined ?
Gnoma [55]

Particles in a gas are far apart compared to a solid or liquid, allowing it not to have a definitive shape or volume. This also means that gases can fill any container and be easily compressed.

4 0
3 years ago
How is good at electron configurations in chemistry?
Paha777 [63]

Try to understand all the rules and laws like:

Aufbau Principle

Hund's rule

Pauli exclusion principle...

Then, you should understand the way in which you can fill the electrons in the orbitals!!

8 0
3 years ago
What is a solution considered to be if it has a ph lower than 7?
wariber [46]
Anything less that 7, would be a base.
6 0
3 years ago
Other questions:
  • How many grams are in one mole of phosphide?
    10·1 answer
  • What is the formula mass of silver
    5·1 answer
  • How many electrons in an atom could have n = 2, l = 1, ml = 0?
    9·1 answer
  • Complete the equations showing how 2−phenylethanol (c6h5ch2ch2oh) could be prepared from 2−phenylethanoic acid (c6h5ch2co2h) as
    9·1 answer
  • The equation, H2SO4 (aq) + Sr(OH)2 (aq) arrow SrSO4 (aq) + H2O (l), represents what?
    6·2 answers
  • Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
    7·1 answer
  • A very hard substance is composed of atoms that make a network of strong covalent bonds, with no discrete molecules. It is a poo
    14·1 answer
  • Which color???????<br> please help
    12·1 answer
  • Modeling Mitosis and Meiosis
    7·1 answer
  • It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!