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3 years ago

Which substances are released during cellular respiration?

1 answer:

8 0

Answer is: carbon dioxide and water <span>are released during cellular respiration.
</span>Chemical reaction of cellular respiration:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.
There are 18 oxygen atoms (six in glucose and twelve in six molecules of oxygen) in left side of chemical reaction and also 18 oxygen atoms (twelve in six molecules of carbon dioxide and six in six molecules of water) at the right.

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Describe the difference between Al3+<br> and N3-

wariber [46]

Al3+ is cation due to its positve charge
N3- is an anion due to its negative charge

4 0

4 years ago

Hydrogen fuel cells are a promising alternative to gasoline engines in part because they release water instead of carbon dioxide

enot [183]

Answer:

The correct answer is option (B) Two molecules of H2 and a molecule of O2 must collide at one time

Explanation:

2H2(g) + O2(g) → 2 H2O(g)

2 1 2

Considering the given reaction, for water molecule to be form, two molecules of hydrogen and one molecule of oxygen must collide at the same time. The product obtained from the collision is two molecules of water as steam. 2 H2O(g)

6 0

3 years ago

Read 2 more answers

A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling

n200080 [17]

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output / maximum power output

= (actual power output)/(efficiency * rated power output)

$= \frac{1200}{\frac{42}{100}*3000}$

= 0.952

2) Availability factor

Availability factor = Actual operation time period/ total time period

= 23/24 = 0.958

8 0

3 years ago

5. What is the density of water in g/mL? Why?

goldfiish [28.3K]

Answer:

1g/ml @ 4 degrees C by definition

Explanation:

7 0

3 years ago

This table has information about the heat of fusion and the heat of vaporization of different substances. A 3-column table with

blagie [28]

H₂S

<h3>Further explanation</h3>

Given

ΔH fusion and ΔH vaporization of different substances

Required

The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes

Solution

We can use the formula :

$\tt \Delta H=\dfrac{Q}{n}$

Q=heat/energy absorbed

n = moles

The heat absorbed : 58.16 kJ

moles = 3.11

so ΔH vaporization :

$\tt \Delta H_{vap}=\dfrac{58.16~kJ}{3.11~mol}\\\\\Delta H_{vap}=18.7~kJ/mol$

The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S

(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)

3 0

3 years ago

Read 2 more answers