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Gnom [1K]
4 years ago
15

People tend to speak more quietly in restaurants than they do when they are having an ordinary conversation Restaurant conversat

ion is about 45 dB. If ordinary conversation is 100 times greater than restaurant conversation, how loud is ordinary conversation?
Chemistry
1 answer:
MArishka [77]4 years ago
6 0

Answer:

A loud ordinary conversation following the supplied information in the question is about 4500 dB. But, in the official decibel system measure a loud conversation does not overcome 100 dB.

Explanation:

Using the supplied data of the exercise, we say that in a restaurant conversation the value is 45 dB. If we multiply this by 100 we will have a value for a laud ordinary conversation.

45×100 = 4500 dB.

but as I mentioned in the answer, in the official decibel system measure a loud conversation between 2 man reaches a maximal of 100 dB.

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Why do the ocean currents move from the equator towards the poles?
elena-s [515]
Hey there!

The reason why <span>ocean currents move from the equator towards the poles are because the wind push the water's away from the equator and toward the poles, so pretty much, let's blame this on the wind, it's the wind's fault not ours. But yes, your correct answer to this question above would be of that the wind's push the water's away from the equator and to the poles.

Hope this helps you buddy!</span>
4 0
4 years ago
Please give formulas of how you solved I only need help on a but if you can do all that I would appreciate that.​
cricket20 [7]

Answer:

3.1 moles of ammonia

18.67× 10²³ molecules

Mass = 52.7 g

Explanation:

Given data:

Number of atoms of hydrogen = 5.68×10²⁴ atoms

A) Number of molecules of ammonia = ?

Solution:

First of all we will calculate the number of moles of hydrogen.

1 mole = 6.022× 10²³ atoms

5.68×10²⁴ atoms × 1 mol / 6.022× 10²³ atoms

0.94×10¹ mol

9.4 moles of hydrogen

Moles of ammonia:

3 moles of hydrogen are present in one mole of ammonia.

9.4 moles of hydrogen = 1/3×9.4 =

3.1 moles of ammonia

Number of molecules of ammonia:

1 mole contain 6.022× 10²³ molecules.

3.1 mol × 6.022× 10²³ molecules / 1 mol

18.67× 10²³ molecules

c) Mass of sample = ?

Mass = number of moles × molar mass

Mass = 3.1 moles × 17 g/mol

Mass = 52.7 g

4 0
3 years ago
If 2.4 g of n2 gas has a volume of 0.40 l and a pressure of 6.6 atm , what is its kelvin temperature?
Nesterboy [21]

To solve for the absolute temperature, we assume ideal gas behaviour so that we use the equation:

PV = nRT

or T = PV / nR

 

So calculating:

T = [6.6 atm * 0.40 L] / [(2.4g / 28g/mol) * 0.08205746 L atm / mol K]

<span>T = 375.35 K</span>

8 0
3 years ago
A 21.82 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21.33 grams of CO2 and 4
morpeh [17]

<u>Answer:</u> The molecular formula for the given organic compound is C_2H_2O_4

<u>Explanation:</u>

  • The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=21.33g

Mass of H_2O=4.366g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.33 g of carbon dioxide, \frac{12}{44}\times 21.33=5.82g of carbon will be contained.

  • For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 4.366 g of water, \frac{2}{18}\times 4.366=0.485g of hydrogen will be contained.

  • Mass of oxygen in the compound = (21.82) - (5.82 + 0.485) = 15.515 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5.82g}{12g/mole}=0.485moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.485g}{1g/mole}=0.485moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{15.515g}{16g/mole}=0.969moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = \frac{0.485}{0.485}=1

For Hydrogen  = \frac{0.485}{0.485}=1

For Oxygen  = \frac{0.969}{0.485}=1.99\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 1 : 2

Hence, the empirical formula for the given compound is C_1H_{1}O_2=CHO_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

  • The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 90.04 g/mol

Mass of empirical formula = 45 g/mol

Putting values in above equation, we get:

n=\frac{90.04g/mol}{45g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 2)}H_{(1\times 2)}O_{(2\times 2)}=C_2H_2O_4

Thus, the molecular formula for the given organic compound is C_2H_2O_4

4 0
4 years ago
Why is co2 so bad for our bodies and why do we need to remove it? In the context of protons and ions acid/base solution.
dezoksy [38]
Hopefully this is correct and I believe CO2 is bad because the cells in the body need oxygen to then release energy from food efficiently by carrying out aerobic respiration. And a waste product of aerobic respiration is Carbon Dioxide. And Carbon dioxide must be removed from our bodies or it them makes the blood dangerously acidic.


Hope this helps :)
3 0
3 years ago
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