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Tamiku [17]
2 years ago
6

Is Pb --> PbSO4 reduction half reaction?​

Chemistry
1 answer:
Temka [501]2 years ago
7 0

Answer:

No its is the oxidation half

Explanation:

Because Pb lost 2e^{-}

and oxidation is losing, I abbreviate it in (OIL) not oil that used in kitchen

OIL=Oxidation Is Losing electrons

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What was George Washington Caver professional information ​
Sedbober [7]

Explanation:

George Washington Carver was born enslaved and went on to become one of the most prominent scientists and inventors of his time, as well as a teacher at the Tuskegee Institute. Carver devised over 100 products using one major crop — the peanut — including dyes, plastics and gasoline.

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How can you tell if a electron configuration is ground state or excited state?
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How many moles of CO2 are produced from the combustion of 6.40 mol c2h8?
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2 years ago
Please help!!!!its due tomorrow !!!
scZoUnD [109]

#6).
Every 1,000 mL makes 1 L
How many 1,000mL are there in  2,800 mL ?
That's division.
                         (2,800 mL) / (1,000 mL) = <em>2.8 L</em>

#7).
The 'perimeter' means the 'distance all the way around'.
You have to know that both sides of a rectangle are the same length,
and also the top and bottom are the same length.
So the perimeter of this rectangle is

   (2 yd) + (4.5 yd) + (2.yd) + (4.5 yd) = 13 yd .

Oops.  The problem wants to know the perimeter in feet.
So you have to know that each yard is the same as 3 feet.
In order to find the number of feet in 13 yards, you have to
take 3 feet 13 <em><u>times</u></em> .

       (3 feet) times (13)  =  <em>39 feet .</em>

#8).
For this one, you have to know that every 36 inches makes 1 yard.

How many 36 inches are there in 48 inches ?
That's division.
                         (48 inches) / (36inches)  =  <em>1 and 1/2 yards</em> .

#9).
For this problem, you have to know how to handle a mixed number,
and you also have to know that there are 16 ounces in 1 pound.

Add up the fruit:

             (3-1/2 pounds) + (4 pounds) + 2 pounds)  =  <em><u>9-1/2 pounds</u></em>

Now, remember that each pound is the same as 16 ounces.  So if you
want to find the number of ounces in  9-1/2 pounds, you have to take
16 ounces  9-1/2 times .

     (16 ounces) times (9-1/2) = <em>152 ounces</em>.
___________________________________

#10).
This one is just adding up some numbers.  But after you finish doing that, you have to know that  1,000 meters is called '1 kilometer' .

Add up the distances that Omar ran:

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The problem wants to know how many kilometers this is, so you have to figure out how many '1,000 meters' fit into 4,125 meters.

That's division.

   (4,125 meters) / (1,000 meters)  =  <em>4.125 kilometers</em>


4 0
3 years ago
In acidic solution, the breakdown of sucrose into glucose and fructose has this rate law: rate = k[H+][sucrose].
Karo-lina-s [1.5K]

Answer:

a)If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.

b)If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.

c)If concentration of  [H^+] is changed to 0.0001 M than rate will be increased by the factor of 0.01.

d) If concentration when [sucrose] and[H^+] both are changed to 0.1 M than rate will be increased by the factor of 1.

Explanation:

Sucrose +  H^+\rightarrow  fructose+ glucose

The rate law of the reaction is given as:

R=k[H^+][sucrose]

[H^+]=0.01M

[sucrose]= 1.0 M

R=k[0.01M][1.0 M]..[1]

a)

The rate of the reaction when [Sucrose] is changed to 2.5 M = R'

R'=[0.01 M][2.5 M]..[2]

[2] ÷ [1]

\frac{R'}{R}=\frac{[0.01 M][2.5 M]}{k[0.01M][1.0 M]}

R'=2.5\times R

If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.

b)

The rate of the reaction when [Sucrose] is changed to 0.5 M = R'

R'=[0.01 M][0.5 M]..[2]

[2] ÷ [1]

\frac{R'}{R}=\frac{[0.01 M][0.5 M]}{k[0.01M][1.0 M]}

R'=2.5\times R

If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.

c)

The rate of the reaction when [H^+] is changed to 0.001 M = R'

R'=[0.0001 M][1.0 M]..[2]

[2] ÷ [1]

\frac{R'}{R}=\frac{[0.0001 M][1.0M]}{k[0.01M][1.0 M]}

R'=0.01\times R

If concentration of  [H^+] is changed to 0.0001 M than rate will be increased by the factor of 0.01.

d)

The rate of the reaction when [sucrose] and[H^+] both are changed to 0.1 M = R'

R'=[0.1M][0.1M]..[2]

[2] ÷ [1]

\frac{R'}{R}=\frac{[0.1M][0.1M]}{k[0.01M][1.0 M]}

R'=1\times R

If concentration when [sucrose] and[H^+] both are changed to 0.1 M than rate will be increased by the factor of 1.

5 0
3 years ago
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