Answer:
R aluminium = 2.63x10^-6 Ω*cm
Rcopper = 1.7 x10^-6 Ω*cm
I would use Cu as interconnections in advanced CMOS nodes.
Explanation:
the conductivity formula equals:
σ = n*g*u
n = carrier concentration
u = mobility
g = charge of carrier
The resistivity is equal to:
R = 1/σ
For the aluminium, we have:
g = 1.602x10^-19 C
R = 1/(1.98x10^23 * 1.602x10^-19 * 12 = 2.63x10^-6 Ω*cm
For copper:
R = 1/(8.5x10^22 * 1.602x10^-19 * 43.2) = 1.7 x10^-6 Ω*cm
According to the calculations found for both resistivities, I would use Cu as interconnections in advanced CMOS nodes, since copper has a lower resistivity and therefore, copper conducts electricity better.
The volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.
Explanation:
The kinetic theory of gases is mostly based on Boyle's law. From the Boyle's law, the pressure experienced by any gas molecules is inversely proportional to volume of the gas molecules. Also this inverse relation is obeyed if and only if the number of moles and temperature of the gas molecules remained constant.
So,
So if there is a change in pressure then there will be inverse change in volume. That means if there is decrease in the pressure of gas molecules then there will be increase in the volume and vice versa.
So the Boyle's law is combined as 
As here the initial pressure or 
is 1 atm or 101.3 kPa and the initial volume is 478 mL. Similarly, the final pressure is 93.3 kPa and the final volume will be
So, the volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.
Answer:
3.55atm
Explanation:
We will apply Boyle's law formula in solving this problem.
P1V1 = P2V2
And with values given in the question
P1=initial pressure of gas = 1.75atm
V1=initial volume of gas =7.5L
P2=final pressure of gas inside new piston in atm
V2=final volume of gas = 3.7L
We need to find the final pressure
From the equation, P1V1 = P2V2,
We make P2 subject
P2 = (P1V1) / V2
P2 = (1.75×7.5)/3.7
P2=3.55atm
Therefore, the new pressure inside the piston is 3.55atm
The answer is a bonding agent
