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FinnZ [79.3K]
3 years ago
11

The pressure of 5.00 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant tempe

rature?
Chemistry
2 answers:
Vsevolod [243]3 years ago
5 0
(P1)(V1)=(P2)(V2)
(1.50)(5.00)=(1240/760)(V2)
(7.5)/(1240/760)=V2
V2=4.596774194 L
xeze [42]3 years ago
4 0

Answer:

V_2=4.60L

Explanation:

Hello,

In this case, by means of the Boyle's law which allows us to understand a gas' volume-pressure relationship through an inversely proportional relationship:

P_1V_1=P_2V_2

We solve for the final volume V_2 as required, including the conversion from mmHg to atm for the final pressure:

V_2=\frac{P_1V_1}{P_2} =\frac{1.50atm*5.00L}{1240mmHg*\frac{1atm}{760mmHg} } \\\\V_2=4.60L

Regards.

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C₆H₅NH₃⁺(aq) + H₂O(l) → C₆H₅NH₂ + H₃O⁺

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