Generally, the rate of a reaction will decrease with increasing temperature, although there are some exceptions in the case of non-elementary reactions. However it is more likely that the first statement is false.
Half-life is a measure of the time taken for a to reach 1/2 of its initial concentration, and is generally completely independent of reagent concentration within a first order reaction, which is likely what this reaction is, therefore statement 2 is also likely false.
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In the first distillation this week, Hexane from the original solvent makes a larger contribution to the vapor pressure of the mixture.
In between hexane and toluene, the hexane will have more vapor pressure contribution in the solution. The boiling point of hexane is much lower than toluene. Therefore, it will evaporate easily at low temperatures and start exerting pressure on the solution.
Hence between hexane and toluene, because of more vapor pressure of hexane and lower boiling point, it will easily evaporate and exerts pressure.
Therefore, from the original solvent, hexane makes a larger contribution to the vapor pressure of the mixture.
To learn more about vapor pressure and hexane, visit: brainly.com/question/28206662
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Answer:
m H2O = 56 g
Explanation:
∴ The heat ceded (-) by the Aluminum part is equal to the heat received (+) by the water:
⇒ - (mCΔT)Al = (mCΔT)H2O
∴ m Al = 25.0 g
∴ Mw Al = 26.981 g/mol
⇒ n Al = (25.0g)×(mol/26.981gAl) = 0.927 mol Al
⇒ Q Al = - (0.927 mol)(24.03 J/mol°C)(26.8 - 86.4)°C
⇒ Q Al = 1327.64 J
∴ mH2O = Q Al / ( C×ΔT) = 1327.64 J / (4.18 J/g.°C)(26.8 - 21.1)°C
⇒ mH2O = 55.722 g ≅ 56 g
IPSPs are local hyperpolarizations.
Option B
<u>Explanation:</u>
The Inhibitory Post Synaptic Potentials are basically resultant of local hyper polarization and by then they degrade to depolarization. These are synaptic potentials which causes the neuron of post synapse to engage in lesser generation of action potential.
The local hyper polarization is achieved as the post synapse membrane has the negative potential more than that of resting membrane, then the condition becomes hyper polarization. In order to achieve so, the action potential must under go depolarization and hence it degrades to depolarization.
Answer:
1x10^-3M
Explanation:
Data obtained from the question include:
pH = 3
[H3O+] =?
The concentration of the hydronium ion [H3O+] can be obtained by using the formula pH = - Log [H3O+] as illustrated below:
pH = - Log [H3O+]
3 = - Log [H3O+]
Divide through by - 1
- 3 = Log [H3O+]
Take the anti-log of - 3
[H3O+] = 1x10^-3M
Therefore, the concentration of the hydronium ion [H3O+] is 1x10^-3M
