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Svetradugi [14.3K]
3 years ago
8

The flow curve for a certain metal has parameters: strain-hardening

Engineering
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:(a)45,300.24 lb/in/^2

(b)0.255

Explanation:

Given

Strain hardening exponent(n)=0.22

Strength coefficient(k)=54000 lb/in/^2

and we know

\sigma =k\left ( \epsilon \right )^n

where

sigma =true\ stress

\epsilon =true\ strain

(a)True strain=0.45

\sigma =54000\times 0.45^{0.22}

\sigma =45,300.24 lb/in^2

(b)true stress=40,000 lb/in^2

40000=54000\times \epsilon ^{0.22}

\epsilon ^{0.22}=0.7407

\epsilon =0.7407^{4.5454}=0.255

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Eight energy corporations made plans to increase their combined spending on efficiency programs to $50 million per year for the
tangare [24]

Answer:

F=531831381

Explanation:

There are two  ways of doing this question:

1) By Formula

2) By Using  Compound interest Table

By Formula:

F=A*\frac{(1+i)^{n}-1}{i}

Where:

F is future value

A is annual amount per year

i is interest rate

n is number of years

F=50 million*\frac{(1+0.08)^{8}-1}{0.08}

F=531831381

By Using  Compound interest Table:

F=A(F/A,i,n)

From Table F/A at i=8% and n=8 is 10.6366

F=50000000*(10.6366)

F=531830000≅531831381

The difference in two answers is due to decimal points if you take value from table to greater decimal points you will get the exact answer as by using formula.

7 0
3 years ago
George and Ellen Rottweiler encourage their adult daughter Guinevere to break her engagement and continue living in their home,
Andrew [12]

Answer:

Negative feedback

Explanation:

In Biology, negative feedback refers to the counteraction of an effect by its own influence on the process producing it. For instance, the presence of   a high level of a particular hormone in the blood may inhibit further secretion of that hormone.

In other words, in negative feedback, the result of a certain action may inhibit further performance of that action

7 0
3 years ago
A resistor, an inductor, and a capacitor are connected in series to an ac source. What is the condition for resonance to occur?.
vaieri [72.5K]

Answer:if power factor =1 is possible for that.

Explanation:when pf is unity. means 1.

6 0
1 year ago
If it is struck by a rigid block having a weight of 550 lblb and traveling at 2 ft/sft/s , determine the maximum stress in the c
Lelu [443]

This question is incomplete, The missing image is uploaded along this answer below;

Answer:

the maximum stress in the cylinder is 3.23 ksi

 

Explanation:

Given the data in the question and the diagram below;

First we determine the initial Kinetic Energy;

T = \frac{1}{2}mv²

we substitute

⇒ T = \frac{1}{2} × (550/32.2) × (2)²

T = 34.16149 lb.ft

T =  ( 34.16149 × 12 ) lb.in  

T = 409.93788 lb.in

Now, the volume will be;

V = \frac{\pi }{4}d²L

from the diagram; d = 0.5 ft and L = 1.5 ft

so we substitute

V =  \frac{\pi }{4} × ( 0.5 × 12 in )² × ( 1.5 × 12 in )

V = 508.938 in³

So by conservation of energy;

Initial energy per unit volume = Strain energy per volume

⇒ T/V = σ²/2E

from the image; E = 6.48(10⁶) kip

so we substitute

⇒ 409.93788 / 508.938 = σ²/2[6.48(10⁶)]

508.938σ² =  5,312,794,924.8

σ² = 10,438,982.5967  

σ = √10,438,982.5967

σ = 3230.9414  

σ = 3.2309 ksi  ≈ 3.23 ksi    { three significant figures }

Therefore, the maximum stress in the cylinder is 3.23 ksi

8 0
3 years ago
Water flows in a pipeline. At a point in the line where the diameter is 7 in., the velocity is 12 fps and the pressure is 50 psi
PolarNik [594]

Answer:

a)   P₂ = 3219.11 lbf / ft² , b)    P₂ = 721.91 lbf / ft² , c)  P₂ = 5707.31 lbf / ft²

Explanation:

For this exercise we can use the fluid mechanics equations, let's start with the continuity equation, index 1 is for the starting point and index 2 for the end point of the reduction

     A₁ v₁ = A₂ v₂

     v₂ = v₁ A₁ / A₂

The area of ​​a circle is

    A = π r² = π/4  d²

     v₂ = v₁ (d₁ / d₂)²

Let's calculate

    v₂ = 12 (7/3)²

    v₂ = 65 feet / s

Now let's use Bernoulli's equation

     P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

     P₁ - P₂ = ρ g (y₂ –y₁) + ½ ρ (v₂² - v₁²)

Case 1. The pipe is horizontal, so

      y₁ = y₂

      P₁ - P₂ = ½ ρ  (v₂² –v₁²)

      P₂ = P₁ - ½ ρ (v₂² –v₁²)

     ρ = 62.43 lbf / ft³

     P₁ = 50 psi (144 lbf/ ft² / psi) = 7200 lbf / ft²

    P₂ = 7200 - ½ 62.43 / 32 (65² -12²)

    P₂ = 7200 - 3980.89

    P₂ = 3219.11 lbf / ft²

Case 2 vertical pipe with water flow up

        y₂ –y₁ = 40 ft

        P₁ - P₂ = ρ g (y₂ –y₁) + ½ rho (v₂² - v₁²)

        7200 - P₂ = 62.43 (40) + ½ 62.43 / 32 (65 2 - 12 2) =

        P₂ = 7200 - 2497.2 - 3980.89

         P₂ = 721.91 lbf / ft²

Case 3. Vertical water pipe flows down

         y₂ –y₁ = -40

         P₂ = 7200 + 2497.2 - 3980.89

         P₂ = 5707.31 lbf / ft²

3 0
3 years ago
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