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Svetradugi [14.3K]
3 years ago
8

The flow curve for a certain metal has parameters: strain-hardening

Engineering
1 answer:
ZanzabumX [31]3 years ago
3 0

Answer:(a)45,300.24 lb/in/^2

(b)0.255

Explanation:

Given

Strain hardening exponent(n)=0.22

Strength coefficient(k)=54000 lb/in/^2

and we know

\sigma =k\left ( \epsilon \right )^n

where

sigma =true\ stress

\epsilon =true\ strain

(a)True strain=0.45

\sigma =54000\times 0.45^{0.22}

\sigma =45,300.24 lb/in^2

(b)true stress=40,000 lb/in^2

40000=54000\times \epsilon ^{0.22}

\epsilon ^{0.22}=0.7407

\epsilon =0.7407^{4.5454}=0.255

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The break force that must be applied to hold the plane stationary is 12597.4 N

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The break force that must be applied to hold the plane stationary = 12597.4 N.

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