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OverLord2011 [107]
1 year ago
14

Technician a says that personal protective equipment (ppe) does not include clothing. technician b says that the ppe used should

be based on the task you are performing. who is correct?
Engineering
1 answer:
frez [133]1 year ago
4 0

Based on the information provided, the technician who is correct is: B. Technician B.

<h3>What is PPE?</h3>

PPE is an abbreviation for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Additionally, some examples of personal protective equipment (PPE) that are used to protect the different parts of the body are:

  • Respirators
  • Face mask
  • Face shield
  • Gloves
  • Boots
  • Helmet

Based on the information provided, the technician who is correct is Technician B only because PPE should be used based on the task being performed.

Read more on PPE here: brainly.com/question/19131588

#SPJ1

Complete Question:

Technician a says that personal protective equipment (ppe) does not include clothing. technician b says that the ppe used should be based on the task you are performing. who is correct?

Technician A.

Technician B.

Neither Technician A nor Technician B

Both Technician A and Technician B

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There are three options for heating a particular house: a. Gas: $1.33/therm where 1 therm=105,500 kJ b. Electric Resistance: $0.
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Answer:

Option ‘a’ is the cheapest for this house.

Explanation:

Cheapest method of heating must have least cost per kj of energy. So, convert all the energy in the same unit (say kj) and take select the cheapest method to heat the house.

Given:

Three methods are given to heat a particular house are as follows:

Method (a)

Through Gas, this gives energy of amount $1.33/therm.

Method (b)

Through electric resistance, this gives energy of amount $0.12/KWh.

Method (c)

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Calculation:

Step1

Change therm to kj in method ‘a’ as follows:

C_{1}=\frac{\$ 1.33}{therm}\times(\frac{1therm}{105500kj})

C_{1}=1.2606\times10^{-5} $/kj.

Step2

Change kWh to kj in method ‘b’ as follows:

C_{2}=\frac{\$ 0.12}{kWh}\times(\frac{1 kWh }{3600kj})

C_{2}=3.334\times10^{-5} $/kj.

Step3

Change kWh to kj in method ‘c’ as follows:

C_{3}=\frac{\$ 2.30}{gallon}\times(\frac{1 gallon }{138500kj})

C_{3}=1.66\times10^{-5} $/kj.

Thus, the method ‘a’ has least cost as compare to method b and c.

So, option ‘a’ is the cheapest for this house.

 

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DRIVERS ED
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Answer:

b

Explanation:

only if there signal is turned on

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