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jeyben [28]
3 years ago
14

Researchers compared protein intake among three groups of postmenopausal women: (1) women eating a standard American diet (STD),

(2) women eating a lacto-ovo-vegetarian diet (LAC), and (3) women eating a strict vegetarian diet (VEG).GroupMean protein intake (mg)SDnSTD75910LAC571310VEG47176a.Without using MATLAB ANOVA functions, determine if there is a significant difference in mean protein intake between these groups.
Engineering
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

see explaination

Explanation:

The statistical procedure for comparing the 3 groups was the F test with 2 degrees of freedom in the numerator (groups - 1) and 23 df in the denominator (N total - groups)

It is calculated as SSB/2/(SSW/23) = 10.22754

As Fcrit =

from Excel, finv(.05,2,23) = 3.4221, we can reject the null hypothesis of no difference between groups.

SSW = the sum of std i ^ 2 * (n i - 1)

SSB = the sum of ni (mean i - mean)^2

2. From Excel, we get the pvalue from fdist(10.22754,2,23) = .000664

3. For LSD, we calculate (mean 1 - mean 2)/(s * sqrt(1/n1+1/n2))

This is the pooled s = sqrt(SSW/23)

Then, we found t crit from tinv(.05,23) = 2.068

Making use of the chart i made, We found significant differences between std and lac as well as std and veg, but no significant difference between lac and veg.

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Neko [114]

Answer:

Below is the desired C++ program for the problem. Do feel free to edit it according to your preference

Explanation:

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#include <vector>

using namespace std;

void ExactChange(int userTotal, vector<int> &coinVals) {

   coinVals.reserve(5);

   coinVals[0] = userTotal / 100;

   userTotal %= 100;

   coinVals[1] = userTotal / 25;

   userTotal %= 25;

   coinVals[2] = userTotal / 10;

   userTotal %= 10;

   coinVals[3] = userTotal / 5;

   userTotal %= 5;

   coinVals[4] = userTotal;

}

int main() {

   vector<int> coins;

   int value;

   cin >> value;

   if (value <= 0) {

       cout << "no change" << endl;

   } else {

       ExactChange(value, coins);

       if (coins[0] != 0) cout << coins[0] << " " << (coins[0] == 1 ? "dollar" : "dollars") << endl;

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       if (coins[3] != 0) cout << coins[3] << " " << (coins[3] == 1 ? "nickel" : "nickels") << endl;

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   }

   return 0;

}

5 0
3 years ago
The chart describes four people’s credit histories.
icang [17]

Answer:

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7 0
3 years ago
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Fiesta28 [93]
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6 0
2 years ago
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