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natulia [17]
3 years ago
10

Reusable refrigerant containers under high-pressure must be hydrostatically tested how often?

Engineering
1 answer:
timurjin [86]3 years ago
4 0

Answer:

5 years

Explanation:

A hydrostatic testing machine is the equipment used to measure the strength or structural integrity of high pressure vessels that are designed for the transportation of liquids or gas. Among the containers that can be subjected to hydrostatic tests can be found boilers, gas cylinders (transport or storage) and pipes of water and gas systems.

In general, the use of this type of equipment is responsible for ensuring that the different types of containers do not leak in the entire container, pipes and connections, as well as that they are structurally safe to be operated by a person or Otherwise, the risk of leakage or explosion due to high pressure can be very high.

To perform hydrostatic tests on pipes or containers, it is necessary that the object to be evaluated be placed in a steel chamber that is filled with water at normal pressure; subsequently, the pressurized water is pumped into the item being tested, so that the container will expand, forcing the water out of the steel chamber and subsequently the pressure is released, which forces the water to return to The steel chamber.

From this test you can calculate the amount of water that goes out and the one that returns to the steel chamber, which is used to determine if the containers and pipes that are being tested pass or fail the hydrostatic test. From the tests it can be determined if the items are safe for use, if they require repairs or need replacing.

In the case of reusable high pressure refrigerant containers, the tests of said containers must be carried out at least every 5 years to avoid accidents and determine the conditions in which the container is located.

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AVprozaik [17]

Answer:

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Explanation:

3 0
3 years ago
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insens350 [35]

Answer:

answer c

Explanation:

4 0
2 years ago
You want to plate a steel part having a surface area of 160 with a 0.002--thick layer of lead. The atomic mass of lead is 207.19
Pepsi [2]

Answer:

<u><em>To answer this question we assumed that the area units and the thickness units are given in inches.</em></u>

The number of atoms of lead required is 1.73x10²³.    

Explanation:

To find the number of atoms of lead we need to find first the volume of the plate:

V = A*t

<u>Where</u>:

A: is the surface area = 160

t: is the thickness = 0.002

<u><em>Assuming that the units given above are in inches we proceed to calculate the volume: </em></u>

V = A*t = 160 in^{2}*0.002 in = 0.32 in^{3}*(\frac{2.54 cm}{1 in})^{3} = 5.24 cm^{3}    

Now, using the density we can find the mass:

m = d*V = 11.36 g/cm^{3}*5.24 cm^{3} = 59.5 g

Finally, with the Avogadros number (N_{A}) and with the atomic mass (A) we can find the number of atoms (N):

N = \frac{m*N_{A}}{A} = \frac{59.5 g*6.022 \cdot 10^{23} atoms/mol}{207.19 g/mol} = 1.73 \cdot 10^{23} atoms    

Hence, the number of atoms of lead required is 1.73x10²³.

I hope it helps you!

3 0
3 years ago
Four of the minterms of the completely specified function f(a, b, c, d) are m0, m1, m4, and m5.
Sveta_85 [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) The required additional minterms  for f so that f has eight primary implicants with two literals and no other prime implicant are m_{2},m_{3},m_{7},m_{8},m_{11},m_{12},m_{13},m_{14} and m_{15}

b) The essential prime implicant are c' d',a'b',ab and cd

c) The minimum sum-of-product expression for f are

                  a'b' +ab +c'd'+cd+a'c',\\ a'b'+ab+c'd'+cd+a'd,\\a'b'+ab+c'd'+cd+bc'  and  \\ a'b'+ab+c'd' +cd+bd

Explanation:

The explanation is shown on the second third and fourth image

8 0
3 years ago
By adding "-once", one can form the noun form of the word "organize" is that true or false?​
denpristay [2]

Answer:

<h2>False </h2>

Explanation:

The noun form of organize is just adding letter r

7 0
2 years ago
Read 2 more answers
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