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natulia [17]
4 years ago
10

Reusable refrigerant containers under high-pressure must be hydrostatically tested how often?

Engineering
1 answer:
timurjin [86]4 years ago
4 0

Answer:

5 years

Explanation:

A hydrostatic testing machine is the equipment used to measure the strength or structural integrity of high pressure vessels that are designed for the transportation of liquids or gas. Among the containers that can be subjected to hydrostatic tests can be found boilers, gas cylinders (transport or storage) and pipes of water and gas systems.

In general, the use of this type of equipment is responsible for ensuring that the different types of containers do not leak in the entire container, pipes and connections, as well as that they are structurally safe to be operated by a person or Otherwise, the risk of leakage or explosion due to high pressure can be very high.

To perform hydrostatic tests on pipes or containers, it is necessary that the object to be evaluated be placed in a steel chamber that is filled with water at normal pressure; subsequently, the pressurized water is pumped into the item being tested, so that the container will expand, forcing the water out of the steel chamber and subsequently the pressure is released, which forces the water to return to The steel chamber.

From this test you can calculate the amount of water that goes out and the one that returns to the steel chamber, which is used to determine if the containers and pipes that are being tested pass or fail the hydrostatic test. From the tests it can be determined if the items are safe for use, if they require repairs or need replacing.

In the case of reusable high pressure refrigerant containers, the tests of said containers must be carried out at least every 5 years to avoid accidents and determine the conditions in which the container is located.

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kherson [118]

Explanation:

thermal expansion ∝L = (δL/δT)÷L ----(1)

δL = L∝L + δT ----(2)

we have δL = 12.5x10⁻⁶

length l = 200mm

δT = 115°c - 15°c = 100°c

putting these values into equation 1, we have

δL = 200*12.5X10⁻⁶x100

= 0.25 MM

L₂ = L + δ L

= 200 + 0.25

L₂ = 200.25mm

12.5X10⁻⁶ *115-15 * 20

= 0.025

20 +0.025

D₂ = 20.025

as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0

3 0
3 years ago
Only an outer panel is being replaced. Technician A says that removing the spot welds by drilling through both panels allows the
Angelina_Jolie [31]

Answer:

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5 0
3 years ago
A solid cylindrical workpiece made of 304 stainless steel is 150 mm in diameter and 100 mm is high. It is reduced in height by 5
goblinko [34]

Answer:

45.3 MN

Explanation:

The forging force at the end of the stroke is given by

F = Y.π.r².[1 + (2μr/3h)]

The final height, h is given as h = 100/2

h = 50 mm

Next, we find the final radius by applying the volume constancy law

volumes before deformation = volumes after deformation

π * 75² * 2 * 100 = π * r² * 2 * 50

75² * 2 = r²

r² = 11250

r = √11250

r = 106 mm

E = In(100/50)

E = 0.69

From the graph flow, we find that Y = 1000 MPa, and thus, we apply the formula

F = Y.π.r².[1 + (2μr/3h)]

F = 1000 * 3.142 * 0.106² * [1 + (2 * 0.2 * 0.106/ 3 * 0.05)]

F = 35.3 * [1 + 0.2826]

F = 35.3 * 1.2826

F = 45.3 MN

7 0
3 years ago
Force = 33 newtons
kicyunya [14]

Answer:

answer

Explanation:

4 0
3 years ago
3. This material is considered flammable.
almond37 [142]

Answer:

All of the above

Explanation:

Most of materials are flammable because of the chemicals theyre made up of.  Most materials that are bought say to keep them at room temature for a reason.

4 0
2 years ago
Read 2 more answers
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