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3 years ago

Consider the following expression and determine which statements are true.

Mathematics

2 answers:

sveticcg [70]3 years ago

7 0

Answer:

b c d

Step-by-step explanation:

just try it

dusya [7]3 years ago

4 0

Answer:

The expression 2gh – (3 + 7) is a difference.

The expression 3 + 7 is a sum.

The coefficients of the expression are 2 and 1/4

Step-by-step explanation:

Difference means subtraction.

A sum is addition.

Coefficients are what is multiplied to a variable. In this case 2gh x/4

Hope this helped. Have a good day. Please mark brainliest!

You might be interested in

How do you convert 41/8 and 12/1 to common denominators?

Anna [14]

Multiply 8 the numerator and denominator to the second one.
12/1
8(12/1)
96/8
Now they have the same denominators.

6 0

4 years ago

You drove at 55mph for 4.5 hours. Which of the following equations will tell you how far you drove? A: d=(55)(4.5) B: 55=r(4.5)

vesna_86 [32]

A. 55mph x 4.5hrs which makes since because mph is miles per hour, so I drove 55miles every hour.

7 0

3 years ago

Read 2 more answers

A bag contains five tokens numbered 2, 3, 6, 7, and 8. Two tokens are taken in succession out of the bag without replacement. A)

Mice21 [21]

Answer and Step-by-step explanation:

A) Probability of taken two odd numbered token without replacement:

P(3) = 2/5 = 0.4

P(7) = 1/4 = 0.25

Construct a probability distribution:

X 3 7

p(X) 0.4 0.25

B) Mean of the probability distribution:

E(X) = ∑xp

E(X) = 3*0.4 + 7*0.25

E(X) = 2.95

Variance of the probability distribution:

V(X) = $\Sigma X^{2}p - [E(X)]^{2}$

V(X) = $3^{2}*0.4+7^{2}*0.25 - (2.95)^{2}$

V(X) = 7.1475

Mean and variance of the probability distribution are 2.95 and 7.145, respectively.

3 0

3 years ago

evablogger [386]

Answer:

C = 13

Step-by-step explanation:

A²+B²=C²

where c is the hypothenuse

5²+12²=c²

25+144=c²

169=c²

√169 = c

13 = c

8 0

2 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

4 0

4 years ago