Answer:
12 kg
Explanation:
q = 52,800 J
c = 880 J/(kg * K) Pretty sure you missed the kg here
ΔT = 5 °C = 5 K (reminder that this only applies to ΔT and not T)
q = mcΔT ⇒ m = q/(cΔT) = 52,800 J / (880 J/(kg * K) * 5 K) = 12 kg
Answer:
Explanation:
= Rate at which the distance between A and starting point of B is changing = -20 km/h
= Rate at which the distance of B is changing = 15 km/h
= Rate at which the distance between A and B is changing
Time after which the rate at which the distance between A and B is changing is 4 hours
Distance covered by A in 4 hours = 
a = Distance remaining to the start point of B = 
b = Distance covered by B in 4 hours = 
Distance between A and B after 4 hours
Differentiating with respect to time we get
The rate at which the distance between the ships is changing at 4 PM is .
a. The force applied would be equal to the frictional
force.
F = us Fn
where, F = applied force = 35 N, us = coeff of static
friction, Fn = normal force = weight
35 N = us * (6 kg * 9.81 m/s^2)
us = 0.595
b. The force applied would now be the sum of the
frictional force and force due to acceleration
F = uk Fn + m a
where, uk = coeff of kinetic friction
35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)
uk = 0.533
second question: How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time?
Answer in units of s.
Answer:
Part 1: 28°
Part 2: 1.367
Explanation:
Part 1:
Given: 62°
Simple
θ = 90°- 62°
<u>θ = 28°</u>
Part 2:
Y-direction
Δy
![0=[16.2sin(62)]t_{1}+1/2(-9.8)t_{1}^{2} \\](https://tex.z-dn.net/?f=0%3D%5B16.2sin%2862%29%5Dt_%7B1%7D%2B1%2F2%28-9.8%29t_%7B1%7D%5E%7B2%7D%20%5C%5C)
![t_{1} =\frac{2[16.2sin(62)]}{9.8}](https://tex.z-dn.net/?f=t_%7B1%7D%20%3D%5Cfrac%7B2%5B16.2sin%2862%29%5D%7D%7B9.8%7D)
![0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}](https://tex.z-dn.net/?f=0%3D%5B16.2sin%2828%29%5Dt_%7B2%7D%2B1%2F2%28-9.8%29t_%7B2%7D%5E%7B2%7D)
![t_{2} =\frac{2[16.2sin(28)]}{9.8}](https://tex.z-dn.net/?f=t_%7B2%7D%20%3D%5Cfrac%7B2%5B16.2sin%2828%29%5D%7D%7B9.8%7D)
Δt
Δt
<u>Δt= 1.367s</u>
Hope it helps :)
Answer:
F = 10.86 units
Explanation:
The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:
F = √(Fₓ² + Fy²)
where,
F = Magnitude of the Vector = ?
Fₓ = magnitude of the x-component of vector = 8.7 units
Fy = magnitude of y component of vector = - 6.5 units
Therefore, using these values in the equation, we get:
F = √[(8.7 units)² + (- 6.5 units)²]
F = √(117.94 units²)
<u>F = 10.86 units</u>
