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Marina86 [1]
3 years ago
9

The scale factor from the model of a human inner ear to the actual ear is 55:2. If one of the bones of the model is 8.25 centime

ters long, how long is the actual bone in a human ear. Please help me
Mathematics
1 answer:
Ratling [72]3 years ago
8 0
Model:actual
55 : 2
27.5 : 1(divide by 2)
8.25: 3.33(3s.f.) (divide by 8.25)
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the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8
uysha [10]

Answer:

12

Step-by-step explanation:

Given :

                                    Male         Female        Total

Registered                                                          60

Non registered                                                   40

Total                          20                  80    

Solution :

N= 100

Formula of expected frequency = E_{ij}=\frac{T_i \times T_j}{N}

E_{ij}= expected frequency for the ith row/jth columm.

T_i = total in the ith row

T_j= total in the jth column

N = table grand total.

So, using formula  E_{11}=\frac{T_1 \times T_1}{100}

E_{11}=\frac{60 \times 20}{100}

E_{11}=12

E_{12}=\frac{T_1 \times T_2}{100}

E_{12}=\frac{60 \times 80}{100}

E_{12}=48

E_{21}=\frac{T_2 \times T_1}{100}

E_{21}=\frac{40 \times 20}{100}

E_{21}=8

E_{22}=\frac{T_2 \times T_2}{100}

E_{22]=\frac{80 \times 40}{100}

E_{22}=32

Expected frequency table

                                    Male         Female        Total

Registered                  12                  48            60

Non registered           8                   32             40

Total                           20                  80    

So, the expected frequency for males who are registered voters are  E_{11}=12

5 0
3 years ago
Heyyyy help me out please? don’t scam please!
OLEGan [10]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Mr and mrs. Dorsey and their three children are fling to Springfield. The cost of each ticket is $179. Estimate how much the tic
Soloha48 [4]
<span>First figure out how many people there are all together. So mrs and mr is 2 there three children so 2+3=5 so next round 179 to 200 and multiply 200x5. To do that you can use the mental math way witch would be to take the whole number out of 200 and make it 2. Then take the 5 in 200x5 and multiply 2x5. Then add the 2 zeros there were. And your estamated answer would be 1,000.
2+3=5
179=200
200x5
2x5=10
1,000
To figure out your real answer you will have to take 179 and multiply it by 5 so it will look like this:
 34
179
x
   5
895
Soto conculde the answer would be:

Estamated: $1,000

Exact: $895

Hope this helps!</span>
7 0
3 years ago
What is y=-10x's constant of proportionality and how would describe a graph's constant rate of change.
Fantom [35]
Okay, so here, we know that -10 is the slope, therefore, it is also the constant of proportionality. 

'x' is the unknown value, that tells us to multiply by -10. 

So, on a graph, we would consider that per unit, it would decrease by -10, since its a negative slope. 

Hope I helped, if you have further questions or concerns, feel free to PM me. Thanks! :D
5 0
3 years ago
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