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jok3333 [9.3K]
3 years ago
7

Light travels 300,000,000 m/s, and one year has approximately 32,000,000 seconds. a light year is the distance light travels in

one year. state the speed in km/s, using scientific notation
Physics
2 answers:
nikitadnepr [17]3 years ago
8 0

Answer:

A light-year is a unit of distance. It is the distance that light can travel in one year. Light moves at a velocity of about 300,000 kilometers (km) each second. So in one year, it can travel about 10 trillion km. More p recisely, one light-year is equal to 9,500,000,000,000 kilometers.

Explanation:

i just finished that section in school in edge

ps: can you name me the brainiest answer

irina [24]3 years ago
6 0
300 000 000 m/s  in km/s

1000 m = 1km

300 000 000 m/s  = 3 * 10⁸ m/s =  3 * 10⁵ *10³ m/s

=  3 * 10⁵ *10³ m/s

= 3 * 10⁵ km/s

Speed = 3 * 10⁵ km/s
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Answer:

105.8 m

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Explanation:

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3 years ago
a grinding wheel is initially rotating with an angular velocity 5500 rad/srad/s when its motor is suddenly turned off. it comes
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The angle through which the grinding wheel rotates in the first second =  <u>5300 rad</u>

Angular velocity is, the time charge at which an object rotates, or revolves, about an axis, or at which the angular displacement between our bodies changes. within the discern, this displacement is represented via the angle θ among a line on one body and a line on the alternative.

The angular velocity is described as the charge of trade of the angular position of a rotating body. Linear speed is defined because the charge of change of displacement with respect to time whilst the item moves alongside a straight course.

Initial angular velocity of the grinding wheel = ω1 = 5500 rad/s

Final angular velocity of the grinding wheel = ω2 = 0 rad/s   (Comes to rest)

Time is taken by the grinding wheel to come to rest = T = 10 sec

Angular acceleration of the grinding wheel = α

2 = ω1 + αT

0 = 5500 + α(10)

α = - 400 rad/s2

Negative as it is deceleration.

The angle through which the grinding wheel rotates in the first second = θ

Time period = T1 = 1 sec

θ = ω₁T1 + αT1²/2

θ = (5500)(1) + (-400)(1)²/2

θ = 5300 rad

The angle through which the grinding wheel rotates in the first second =  <u>5300 rad</u>

Learn more about angular velocity here:-brainly.com/question/6860269

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