Explanation:
see the above attachment to solve the question and get the answer.
hope this helps you.
Answer:48 V
Explanation:
Given
Three charged particle with charge



Electric Potential is given by

Distance of
from 



similarly 




Potential at
is

![V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]](https://tex.z-dn.net/?f=V_%7Bnet%7D%3Dk%5B%5Cfrac%7Bq_1%7D%7Bd_1%7D%2B%5Cfrac%7Bq_2%7D%7Bd_2%7D%2B%5Cfrac%7Bq_3%7D%7Bd_3%7D%5D)
![V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}](https://tex.z-dn.net/?f=V_%7Bnet%7D%3D9%5Ctimes%2010%5E9%5B%5Cfrac%7B50%7D%7B10%7D-%5Cfrac%7B80%7D%7B12%7D%2B%5Cfrac%7B70%7D%7B10%7D%5D%5Ctimes%2010%5E%7B-9%7D)


The answer is "156.6 m/s".
This is how we calculate this;
-N + mg = ma = mv²/r
For "weightlessness" N = 0, so
0 = mg - mv²/r
g - v²/r = 0
v =√( gr)
g = 9.8 and r = 2.5km = 2500 m
v = √(9.8 x 2500)
= 156.6 m/s
It’d fall 29.4m or 96.46ft
Explanation:
Uhh since gravity is 9.8m/s then in three seconds it’d drop 29.4m or 96.46ft
That is assuming there isn’t a lot of wind resistance, but if you take that into account, then it’d probably be somewhere around 25m since the water bottle is going to be heavier than the wind resistance, and since we don’t know the weight of the water bottle it can’t really be calculated.
Hope this helps!
I believe your answer to be Newtons? Im pretty sure it is though!
If this was the appropiate answer make sure to mark as the brainliest!
-procklown