The focus of an earthquake is internal and is harder to record than the waves of an epicenter, which are on the surface.
Answer:
9.60 m/s
Explanation:
The escape speed of an object from the surface of a planet/asteroid is given by:

where
G is the gravitational constant
M is the mass of the planet/asteroid
R is the radius of the planet/asteroid
In this problem we have
is the density of the asteroid
is the volume
So the mass of the asteroid is

The asteroid is approximately spherical, so its volume can be written as

where R is the radius. Solving for R,
![R=\sqrt[3]{\frac{3V}{4\pi}}=\sqrt[3]{\frac{3(3.09\cdot 10^{12} m^3)}{4\pi}}=9036 m](https://tex.z-dn.net/?f=R%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3%283.09%5Ccdot%2010%5E%7B12%7D%20m%5E3%29%7D%7B4%5Cpi%7D%7D%3D9036%20m)
Substituting M and R inside the formula of the escape speed, we find:

Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm
Answer:
M= F^n / a+g
Explanation:
This shows correctly Newton’s second law, where sum of forces is divided by mass is equal to acceleration. Also mass can’t be negative so F^n is positive.