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Anuta_ua [19.1K]
3 years ago
6

A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds

of its travel What i
average speed during the time from t=5 seconds tot 10 seconds?
A.
B.
2 meters/second
3 meters/second
C.
4 meters/second
D.
5 meters/second
E.
6 meters/second

Chemistry
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

\large \boxed{\text{C. 4 m/s}}

Explanation:

At 5 s the body has travelled 10 m.

Between 5 s and 10 s, the body reached 30 m.

Distance travelled = 30 m - 10 m = 20 m

Time = 10 s - 5 s = 5 s

\text{Speed} = \dfrac{\text{ distance}}{\text{time}} = \dfrac{\text{20 m}}{\text{5 s}} = \textbf{4 m/s}\\\\\text{The average speed between 5 s and 10 s is $\large \boxed{\textbf{4 m/s}}$}

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According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.

<h3>How to calculate the amount of solute that precipitates out of solution?</h3>

To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:

  • Quantity of solute at 80°C: 170 grams.
  • Quantity of solute at 20°C: 40 grams.

  • 170 grams - 40 grams = 130 grams

According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.

Note: This question is incomplete because the graph is missing. Here is the graph

Learn more about solute in: brainly.com/question/7932885

#SPJ1

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