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3 years ago

A kite suspended in the sky is flowing back and forth. Which type of friction is being described?

Physics

2 answers:

solniwko [45]3 years ago

7 0

It would be fluid friction.

PilotLPTM [1.2K]3 years ago

7 0

Answer:

Fluid friction - in fluid friction, there is something called air resistance. This makes fluid friction happen in liquids AND in gases.

Explanation:

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Light travels 186,282 miles in one second. A light year is the distance light travels in one year. It is about 4.3 light years t

deff fn [24]

Answer:

$2.5278035226\times 10^{13}\ miles$

1994.7944465 miles

46390568.5227 miles

125 ft

Explanation:

$1\ ly=186282\times 365.25\times 24\times 60\times 60=5.8786128432\times 10^{12}\ mi$

$4.3\ ly=4.3\times 5.8786128432\times 10^{12}=2.5278035226\times 10^{13}\ miles$

The distance is $2.5278035226\times 10^{13}\ miles$

$2000\ miles=0.01\ in$

$2.5278035226\times 10^{13}\times \dfrac{1}{2000}=1.2639017613\times 10^{10}\ LA\ to\ NY$

Converting to inches

$1.2639017613\times 10^{10}\times 0.01=126390176.13\ in/LA\ to\ NY$

Converting to miles

$126390176.13\times\dfrac{1}{5280\times 12}=1994.7944465\ inches/LA\ to\ NY$

The distance is 1994.7944465 miles

$5.8786128432\times 10^{17}\times \dfrac{1}{2000}\times 0.01\times\dfrac{1}{5280\times 12}=46390568.5227\ miles$

The distance is 46390568.5227 miles

$5.8786128432\times 10^{12}\times 15\times 10^{9}=8.8179192648\times 10^{22}$

$8.8179192648\times 10^{22}\times \dfrac{1}{5.8786128432\times 10^{17}}=150000\ MW\ dia$

$150000\dfrac{1}{100\times 12}=125\ ft$

The distance is 125 ft

5 0

4 years ago

A wheel accelerates so that it's angular speed increases uniformly from 150 rads/s to 580 rads/s in 16 revolutions.Cakcjlate its

LenaWriter [7]

Answer:

A = 26.875 rad/s²

Explanation:

<u>Given the following data;</u>

Initial angular speed, Uw = 150 rads/s.

Final angular speed, Vw = 580 rads/s.

Time = 16 seconds.

To calculate the angular acceleration;

From kinematics equation;

At = Vw - Uw

Where;

A is the angular acceleration.
t is the time
Vw is the final angular speed.
Uw is the initial angular speed.

Substituting into the formula, we have;

A*16 = 580 - 150

16A = 430

A = 430/16

3 0

3 years ago

If a constant fotce of 490 newtons is applied to an object and it proceeds to accelerate in the opposjte direction at 9.8 meters

Sloan [31]

Answer:

50 kg

Explanation:

f=ma

Force = mass x acceleration

490 = 9.8 x m

m = 50 kg

8 0

3 years ago

The force stretching the D string on a certain guitar is 130 N. The string's linear mass density is 0.006 kg/m. What is the spee

inysia [295]

Answer:

The value is $v = 147.2 \ m/s$

Explanation:

From the question we are told that

The force is $F = 130 \ N$

The linear mass density is $\mu = 0.006 \ kg/m$

Generally the speed of the wave on the string is mathematically represented as

$v = \sqrt{\frac{F}{\mu } }$

=> $v = \sqrt{\frac{130}{0.006} }$

=> $v = 147.2 \ m/s$

3 0

3 years ago

Una rueda que gira a 300 r.P.M. Aumenta su velocidad bajo una aceleración angular de 6 2 s rad : calcula: a) La velocidad angula

Rina8888 [55]

Answer:

a) w = 873 rev, b) θ = 97.75 rev

Explanation:

This is a rotation kinematics exercise

w = w₀ + α t

θ = θ₀ + w₀ t + ½ α t²

let's start by reducing the magnitudes to the SI system

w₀ = 300 rpm (2pi rad / 1 rev) (1 min / 60s) = 31.42 rad / s

α = 6 rad / s²

a) let's look for the angular velocity

w = 31.42 + 6 10

w = 91.42 rad / s

b) θ₀ = 0

θ = 0 + 31.42 to + ½ 6 10²

θ = 614.2 rad

As they ask for the result in rpm and revolutions, let's carry out the reduction

w = 91.42 rad / s (1 rev / 2pi rad) (60 s / 1min)

w = 873 rev

θ = 614.2 rad (1 rev / 2pi rad)

θ = 97.75 rev

8 0

3 years ago