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3 years ago

A gas in a rigid container has a pressure of 3.5 atm at 200. k calculate the pressure at 273 k

Chemistry

1 answer:

rusak2 [61]3 years ago

6 0

Answer:

4.78atm

Explanation:

From the question, we obtained the following:

P1 (initial pressure) = 3.5 atm

T1 (initial temperature) = 200K

T2 (final temperature) = 273K

P2 (final pressure) =?

Using P1/T1 = P2/T2, the final pressure can be obtained as shown below:

P1/T1 = P2/T2

3.5/200 = P2/273

Cross multiply to express in linear form as shown below:

200 x P2 = 3.5 x 273

Divide both side by 200

P2 = (3.5 x 273)/200

P2 = 4.78atm

Therefore, the pressure at 273K is 4.78atm

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At equilibrium at 2500K, [HCl]=0.0625M and [H2]=[Cl2]=0.00450M for the reaction H2+Cl2 ⇌ HCl.

ASHA 777 [7]

Answer:

a. $H_2+Cl_2 \rightleftharpoons 2HCl$

b. K = 192.9

c. Products are favored.

Explanation:

Hello!

a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:

$H_2+Cl_2 \rightleftharpoons 2HCl$

In order to reach 2 hydrogen and chlorine atoms at both sides.

b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:

$K=\frac{[HCl]^2}{[H_2][Cl_2]}$

Therefore, we plug in the data to obtain:

$K=\frac{(0.0625)^2}{(0.00450)(0.00450)}\\\\K=192.9$

c. Finally, we infer that since K>>1 the forward reaction towards products is favored.

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8 0

3 years ago

Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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3 years ago

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ValentinkaMS [17]

When grapes become fermented, they turn into wine.

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dusya [7]

This is the definition of a DNA mutation.

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3 years ago

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2KClO3 —> 2KCl2+ 3O2

garik1379 [7]

Answer:

False. The balanced equation should be

2KClO3-->2KCl + 3O2

it is a decomposition reaction.

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3 years ago