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3 years ago

What is the systematic name of the following compound? Li2S

Chemistry

1 answer:

Nuetrik [128]3 years ago

6 0

Answer:

the systematic name is called Lithium sulfide.

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At standard temperature and pressure, 1 mole of gas has what volume? A. 2.4 liters B. 22.4 liters C. 42.4 liters D. 76.6 liters

LekaFEV [45]

Answer: B.22.4 liters

Explanation:

When we attribute to a certain fixed mass of a given gas a fixed number of molecules. Avogadro considered that the mass of 36g of oxygen at any temperature and pressure would have a fixed number of molecules to which he called 1 mol of molecules. So by definition 1 mole of molecules would have a number of molecules equal to that present in 36 g of oxygen. The occupied volume by one mole of molecules at a given temperature and pressure is called molar volume and consists in 22,4 Liters. The molar volume matches the Avogadro Hypothesis (created in 1811 by Amedeo Avogadro), where equal volumes of different gases, at the same temperature and pressure, have even number of moles.

8 0

3 years ago

Mg (s) + 2 HCl (aq) --> MgCl2 (aq) + H2 (g)

MrMuchimi

Answer:

2Mg + 4HCl (aq) --> 2 MgCl2 (aq) + H2

Explanation:

balanced...

4 0

3 years ago

The molar mass of an element is the mass of one

allochka39001 [22]

Answer:

The molar mass of an element is the mass of one mole of atoms of the element.

Explanation:

The molar mass of an element is its atomic mass, i.e. the mass in grams of one mole of atoms of the element.

Remember 1 mol is approximately 6.022 × 10²³.

So, 1 mol of atoms is 6.022 × 10²³ atoms.

The molar mass is an average: it is the weighted average mass of the natural isotopes of the element, taking into account their relative abundance.

For example, the molar mass or atomic mass of carbon is 12,0107 g/mol, instead of 12.0000, becasue carbon exists in several forms (isotopes), and so the weighted average is not a whole number.

7 0

3 years ago

Which of these molecules is nonpolar? a.CH3CI b.CO c.O2 d.PF3

valentina_108 [34]

Answer:

i think the answer is D

Explanation:

7 0

2 years ago

Read 2 more answers

Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.

bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr (1)

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = 181,66 kJ/mol

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = 0,216 kJ/Kmol

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ 4. +117,1 kJ/mol

I hope it helps!

5 0

3 years ago