Answer:
305 litres of NO gas will be produced from 916 L of NO₂
Explanation:
Given the balanced equation of the chemical reaction as follows:
3 NO₂ (g) + H₂O( l) —— 2 HNO₃ (l) + NO (g)
Under standard conditions, 3 moles of No₂ will react with 1 mole of water to produce 1 mole of NO gas.
Molar volume of a gas at STP is 22.4 L
Number of moles of NO₂ gas present in 916 L = 916/22.4 = 40.893 moles of NO₂ gas
From the mole ratio of NO₂ to NO in the equation of reaction,
Number of moles of NO that will be produced = 1/3 × 40.893 moles = 13.631 moles of NO gas
Volume of 13.631 moles of NO gas = 13.631 × 22.4
Volume of NO gas produced = 305.334L
Therefore, Volume of NO gas produced from the reaction of 916 L of NO₂ with water = 305 L
D = m / V
13.6 = 8.3 / V
V = 8.3 / 13.6
V = 0.610 mL
hope this helps!
Answer:
44 grams/mole
Explanation:
<u>If 1 mol of XO₂ contains the same number of atoms as 60 g of XO3, what is the molar mass of XO₂?</u>
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60 grams of XO3 is one mole XO3, since it has the same number of atoms as 1 mole of XO2.
Let c be the molar mass of X. The molar mass of XO3 is comprised of:
X: c
3O: 3 x 16 = 48
Total molar mass of XO3 is = <u>48 + c</u>
We know that the molar mass of XO3 = 60 g/mole, so:
48 + c = 60 g/mole
c = 12 g/mole
The molar mass of XO2 would be:
1 X = 12
2 O = 32
Molar mass = 44 grams/mole, same as carbon dioxide. Carbon's molar mass is 12 grams.
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Answer:
0.032 L or 32 mL
Explanation:
Use the dilution equation M1V1 = M2V2
M1 = 9.0 M
V1 = This is what we're looking for.
M2 = 0.145 M
V2 = 2 L
Solve for V1 --> V1 = M2V2/M1
V1 = (0.145 M)(2 L) / (9.0 M) = 0.032 L
Answer:
it has six significant figures