Answer:
The answer to your question is all the formulas in bold has the same empirical formula
Explanation:
Data
Empirical formula CH₂O
Process
To solve this problem factor the subscripts of each formula and compare the result with the empirical formula given.
a) C₂H₄O₂ factor 2 2(CH₂O)
b) C₃H₆O₃ factor 3 3(CH₂O)
c) CH₂O₂ this formula can not be simplified
d) C₅H₁₀O₅ factor 5 5(CH₂O)
e) C₆H₁₂O₆ factor 6 6(CH₂O)
2 days. 20 grams of carbohydrates
Answer:
when 3-phenylpropanoic, PhCH₂CH₂COOH , is treated with NaOH, H₂0 it produce sodium salt of 3 - phenylpropanoic acid with water as a major product.
Explanation:
Carboxylic acid when treated with a base like NaOH or KOH gives carboxylate ion because H⁺ from acid reacts with OH⁻ from base gives H₂0 and salt of sodium carboxylate.
The mechanism of the above reaction given below
Answer:
What make Boron Boron is that it has 5 protons, and will therefor have 5 electrons in the unionized state. While I was looking this up I learned that there are two stable isotopes, Boron 10 with five neutrons, and boron 11 with six. The more common is boron 11, which is 80.1% of naturally occuring boron.
Answer:
(i) Cl₂ is a limiting reactant
(ii) The amount of excess reactant = 4.8 g
Explanation:
Br₂(g) + Cl₂(g) → 2 BrCl(g) ---------------------------(i)
Calculation of no. of moles


Using mole ratio method to find the limiting reactant and Excess reactant.


So
is a limiting reactant and Br₂ is excess reactant.
The amount of excess reactant = 0.18 - 0.15 = 0.03 mole = 4.8 g