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m_a_m_a [10]
3 years ago
7

. Solve the following problem using analytical techniques: Suppose you walk 18.0 m straight west and then 25.0 m straight north.

How far are you from your starting point, and what is the compass direction of a line connecting your starting point to your final position?
Physics
1 answer:
KiRa [710]3 years ago
7 0

Answer:

H = 30.8 m

\theta =54.25^0

Explanation:

given,

first walks straight west = 18 m

then straight in north = 25 m

the distance from the start point

H² = B² + P²

H² = 18² + 25²

H = \sqrt{18^2+25^2}

H = \sqrt{324+625}

H = 30.8 m

the angle between

tan \theta = \dfrac{P}{B}

tan \theta = \dfrac{25}{18}

\theta = tan^{-1}(\dfrac{25}{18})

\theta =54.25^0

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4 years ago
A fugitive tries to hop on a freight train traveling at a constant speed of 5.0 m/s. Just as a box car passes him, the fugitive
Dima020 [189]

Answer:Given:

Initial speed of fugitive, v0 = 0 m/s

Final speed, vf = 6.1 m/s

acceleration, a = 1.4 m/s^2

Speed of train, v = 5.0 m/s

Solution:

t = (vf-v0)/a

t = (6.1-0)/1.4

t =4.36 s

Distance traveled by train, x_T =v*t

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x_f = 0*4.36+1/2*1.4*4.36^2

x_f =13.31 m

5*t = v(t-4.36)+x_f

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t = 12.08 s

The fugitive takes 12.08 s to catch up to the empty box car.

Distance traveled to reach the box car is

X_T = v*t

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Explanation:

5 0
3 years ago
Explain why the intensity of the light in a flashlight beam decreases as the flashlight moves farther away.
Karolina [17]
Ir=Initial Intensity/Area of spread=Io4πr2
Ir∝1r2

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7 0
3 years ago
A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hittin
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Answer:

-47.04

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8 0
3 years ago
19. A small dog is trained to jump straight up a distance of 1.2 m. How much kinetic energy does the 7.2-kg dog need to jump thi
vova2212 [387]
<span>How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m?
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85 Joule (approx)

Explanation:

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4 0
4 years ago
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