Answer:
608.4m/s
Explanation:
We are given that
Mass of Sleigh,M=1200 kg
Speed of Sleigh,u=322 m/s
Speed of jet,u'=680 m/s
Mass of jet,m=4800 kg
Total mass=M+m=1200+4800=6000 kg
We have to find the final velocity of the two objects after the collision.
The collision is inelastic .
By using law of conservation of momentum
![Mu+mu'=(m+M)v](https://tex.z-dn.net/?f=Mu%2Bmu%27%3D%28m%2BM%29v)
Using the formula
![1200\times 322+4800\times 680=6000v](https://tex.z-dn.net/?f=1200%5Ctimes%20322%2B4800%5Ctimes%20680%3D6000v)
![6000v=3650400](https://tex.z-dn.net/?f=6000v%3D3650400)
![v=\frac{3650400}{6000}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B3650400%7D%7B6000%7D)
![v=608.4m/s](https://tex.z-dn.net/?f=v%3D608.4m%2Fs)
Hence, the final velocity of two objects after the collision=608.4m/s
Work = force x distance. So the answer would be 200x50=10000 joules
I know that the water vapor is the gaseous phase of water. But what is the dew? I just wonder how can I categorized it. Is it the liquid or the gas phase of the water.
Figure below shows dew formed in grass. It seems as a liquid. But is it actually exhibit in liquid phase or gas phase?The answer is water vapor
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Answer:
The object will travel at a constant rate in along a straight line.
Explanation:
In the given situation, it is mentioned that there is no external force acting on the given object. Thus, it will retain its initial velocity along a straight path.
Answer:
The speed of the kid and the skateboard together is 0.723 m/s
Explanation:
Let the mass of the kid be ![m_{k} = 45 kg](https://tex.z-dn.net/?f=m_%7Bk%7D%20%3D%2045%20kg)
Let the mass of the skateboard be ![m_{s} = 4,5 kg](https://tex.z-dn.net/?f=m_%7Bs%7D%20%3D%204%2C5%20kg)
The initial speed of the skateboard, ![v_{s} = 8 m/s](https://tex.z-dn.net/?f=v_%7Bs%7D%20%3D%208%20m%2Fs)
The initial horizontal speed of the boy as he jumps on the skateboard, ![v_{k} = 0 m/s](https://tex.z-dn.net/?f=v_%7Bk%7D%20%3D%200%20m%2Fs)
Let the speed of the kid and the skateboard together be v
According to the principle of conservation of momentum:
![m_{k} v_{k} + m_{s} v_{s} = (m_{k} + m_{s}) v](https://tex.z-dn.net/?f=m_%7Bk%7D%20v_%7Bk%7D%20%2B%20m_%7Bs%7D%20v_%7Bs%7D%20%3D%20%28m_%7Bk%7D%20%2B%20m_%7Bs%7D%29%20v)
Substituting the appropriate values into the given equation
![(45*0) + (4.5*8) = (45 + 4.8) v](https://tex.z-dn.net/?f=%2845%2A0%29%20%2B%20%284.5%2A8%29%20%3D%20%2845%20%2B%204.8%29%20v)
36 = 49.8 v
v = 36/49.8
v = 0.723 m/s