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mart [117]
3 years ago
14

What is the law of reciprocal proportion​

Chemistry
1 answer:
irina [24]3 years ago
7 0

If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other.

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The temperature of a star determines its (science)
Anna007 [38]
The answer would be color. The temperature affects the brightness and the shade of the star.
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3 years ago
Due to radioactive decay over many millions of years, it is possible for the element uranium to decay in
ruslelena [56]

The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.

3 0
3 years ago
a pure sample of a compound on combustion analysis gave 361 mg of CO2 and 147mg of H2O. if the weight of the sample is 202 mg ca
Colt1911 [192]

Answer:

m_C=98.5mgC

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us obtain the mass of carbon in the sample by applying the following stoichiometric factor, considering that the only source of this atom in the sample is contained in the produced 361 mg of CO2 and one mole of this compound contain one mole of carbon atoms whose mass is 12.01 g/mol or mg/mmol as shown below:

m_C=361mgCO_2*\frac{1mmolCO_2}{44.01mgCO_2}* \frac{1mmolC}{1mmolCO_2}*\frac{12.01mgC}{1mmolC}  \\\\m_C=98.5mgC

Regards!

7 0
3 years ago
A new compound contains nitrogen, hydrogen, boron, and fluorine. The assay values are: nitrogen, 13.360%; hydrogen, 3.8455%; bor
AVprozaik [17]

The compound contains:

Nitrogen = 13.360%

Hydrogen = 3.8455%

Boron = 10.312%

This implies that for every 100 g of the substance:

Mass of nitrogen = 13.360 g

Mass of hydrogen = 3.8455 g

Mass of Boron = 10.312 g

Atomic mass of N = 14 g/mol

Atomic mass of H = 1 g/mol

Atomic mass of B = 11 g/mol

# moles of N = 13.360/14 = 0.9543

# moles of H = 3.8455/1 = 3.8455

# moles of B = 10.312/11 = 0.9375

Divide by the smallest # moles:

N = 0.9543/0.9375 = 1.02

H = 3.8455/0.9375 = 4.10

B = 0.9375/0.9375 = 1

Empirical formula = NH4B

4 0
3 years ago
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Name at least 4 other gases in the atmosphere besides oxygen and nitrogen
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<span><span>Argon,</span><span>Carbon dioxide,</span><span>Neon,</span><span>Helium, and </span><span>Methane</span></span>
5 0
4 years ago
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