All categories

3 years ago

What is the law of reciprocal proportion

1 answer:

7 0

If two different elements combine separately with a fixed mass of a third element, the ratio of the masses in which they do so are either the same as or a simple multiple of the ratio of the masses in which they combine with each other.

You might be interested in

H2 is a molecule, but H2O is a _____. 1.diatomic molecule, 2.compound, 3.neuron, 4.photon,

Sonbull [250]

H2O is a compound. So it's second one.

8 0

3 years ago

Which statement is true about SO4 2− ?

Nonamiya [84]

It is a poly atomic anion because it has more than one atom and a negative charge

4 0

3 years ago

Read 2 more answers

What is the name of group 5a

EastWind [94]

Answer:

It is called Pnictogens.

Explanation:

This word is fro a greek word called pnigein which means choking due to a choking property of nitrogen gas when opposed to air with (oxygen).

5 0

3 years ago

The element Osminum has a density of 22.6 g/cm3. the mass of a block of Osmium with three sides of 1.01cmx0.223 cm x 0.648 cm is

Alika [10]

Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3

Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g

6 0

3 years ago

The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con

bonufazy [111]

Answer: The concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

Explanation:

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

We are given:

$t_{1/2}=3.82days$

Putting values in above equation, we get:

$k=\frac{0.693}{3.82}=0.181days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.181days^{-1}$

t = time taken for decay process = 3.00 days

$[A_o]$ = initial amount of the reactant = $1.45\times 10^{-6}mol/L$

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}$

$[A]=3.83\times 10^{-30}mol/L$

Hence, the concentration of radon after the given time is $3.83\times 10^{-30}mol/L$

7 0

4 years ago

What is the law of reciprocal proportion​

What is the law of reciprocal proportion