When an acid is neutralized by a base, that means moles of H+ = moles of OH-
moles of H+ = 0.5 M * 0.025 L HCl = 0.0125 moles H+
moles of OH- should be equal to 0.0125 moles, so
0.0125 moles = (x) * 0.025 L NaOH
x is the concentration of NaOH, which we want to find.
x = 0.5 M
The correct answer is C) 0.5 M.
Answer:
The endpoint volume is 50.52 ± 0.14 mL
Explanation:
In a titration always is necessary to subtract the blank volume to the titrant volume to obtain the real volume of the titrant. Thus in this case, the total endpoint volume is the sum of the initial volume delivered and the second volume delivered, minus the blank volume:
V = (49.16±0.06 mL) + (1.69±0.04 mL) - (0.33±0.04 mL)
V = (49.16 + 1.69 - 0.33) ± (0.06+0.04+0.04) mL
V = 50.52 ± 0.14 mL
It is necessary to consider the sum of the errors too.
The gas inside the can and the can’s volume are both constant.
The gas pressure increases with increasing temperature.
The can will burst if the pressure becomes great enough.
The gas law that applies is Gay-Lussac’s law.
0.05 * V1 = 250 * 10
<span> V1 = 2500 / 0.05 </span>
<span> V1 = 2500 * 20 </span>
<span> V1 = 50000 mL </span>
<span>V1 = 50 Liters .
Hope this helped! :3</span>
We are given with 500 mg of sucrose dissoved in a 200 ml of water. The concentration of the solid is amount of solute per volume of the solvent. The concnetration can be expressed as 2.5 grams sugar per liter water or 250 mg per 100 ml water.
