Answer:
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Explanation:
Given data:
Mass of water = 50 g
Initial temperature= T1 = 20°C
Final temperature= T2 = 10°C
Specific heat of water= c = 4.186 J/g. °C
Amount of heat released = Q= ?
Solution:
Formula:
Q = m. C. ΔT
ΔT = T2 - T1
ΔT = 10°C - 20°C
ΔT = -10°C
Now we will put the values in formula.
Q = m. C. ΔT
Q = 50 g . 4.186 J/g. °C . -10°C
Q = - 2093 J
The amount of heat released when 50 g of water cooled from 20°C to 10°C will be equal to - 2093 J.
Evaporation because the salt would dissolve in the water then boil the water and it will evaporate leaving the salt left in the bowl
Answer:
Explanation:
It rises Food in your stomach (Food slows down alcohol absorption. What's the best to eat? Protein! It takes the longest to digest)
To convert from moles to grams you divide by the molar mass of the element. To convert from grams to moles you X by the molar mass element
