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3 years ago

A quantity of NaCl was dissolved in 100 cm of solution to obtain

Chemistry

1 answer:

soldi70 [24.7K]3 years ago

7 0

Answer:

2.93g

Explanation:first, let us calculate the number of mole of NaCl present in the solution. This is illustrated below:

Molarity = 0.5M

Volume = 100cm^3 = 100/1000 = 0.1L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole of NaCl = 0.5 x 0.1 = 0.05mole

Now we can obtain the mass of NaCl as follows:

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mole of NaCl = 0.05mol

Mass of NaCl =?

Mass = number of mole x molar Mass

Mass of NaCl = 0.05 x 58.5

Mass of NaCl = 2.93g

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The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r

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Explanation:

Given that:

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we can use the formula for Arrhenius equation;

$K=Ae^{\frac{-E}{RT}}$

If $K_1=Ae^{\frac{-E_1}{RT}} -------equation 1$ &

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