All categories

2 years ago

Mole Conversion: How many atoms are in 0.830 moles of gold?

Chemistry

1 answer:

denis23 [38]2 years ago

6 0

Answer:

<h2>4.99 × 10²³ atoms</h2>

Explanation:

The number of atoms of gold can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.83 × 6.02 × 10²³

We have the final answer as

<h3>4.99 × 10²³ atoms</h3>

Hope this helps you

You might be interested in

A chemical reaction takes place in a closed system. The mass of the reactants before the reaction was grams. What must the mass

Ad libitum [116K]

Answer:

D. 25 grams

Explanation:

I think that's what the answer is

7 0

2 years ago

How many liters of N2 gas is needed to produce 500 L NH3?

Veseljchak [2.6K]

I think the answer is 101.2 L

6 0

3 years ago

How to do lewis dot structure of nh3conh3

wlad13 [49]

Answer:

i'm not really sure i cant help today try a different question that i can help u with

Explanation:

3 0

2 years ago

Helllppppppppp Don’t Guess

ruslelena [56]

Answer:

C. Lithium

Explanation:

I Goo gled it and I think that's right.

3 0

2 years ago

Two moles of an ideal gas are placed in a container whose volume is 2.3 x 10^-3 m3. The absolute pressure of the gas is 6.9 x 10

PtichkaEL [24]

Answer:

$K.E.=1.97\times 10^{-21}\ J$

Explanation:

Given that:-

Pressure = $6.9\times 10^5\ Pa$

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = $\frac {1}{101325}$ P (atm)

Given the value of pressure = 43,836 Pa

So,

$6.9\times 10^5\ Pa$ = $\frac{6.9\times 10^5}{101325}$ atm

Pressure = 6.80977 atm

Volume = $2.3\times 10^{-3}\ m^3$ = 2.3 L ( 1 m³ = 1000 L)

n = 2 mol

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T

⇒T = 95.39 K

The expression for the kinetic energy is:-

$K.E.=\frac{3}{2}\times K\times T$

k is Boltzmann's constant = $1.38\times 10^{-23}\ J/K$

T is the temperature

So, $K.E.=\frac{3}{2}\times 1.38\times 10^{-23}\times 95.39\ J$

$K.E.=1.97\times 10^{-21}\ J$

3 0

2 years ago

Mole Conversion: How many atoms are in 0.830 moles of gold? ​

Mole Conversion: How many atoms are in 0.830 moles of gold?