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daser333 [38]
3 years ago
13

Mole Conversion: How many atoms are in 0.830 moles of gold? ​

Chemistry
1 answer:
denis23 [38]3 years ago
6 0

Answer:

<h2>4.99 × 10²³ atoms</h2>

Explanation:

The number of atoms of gold can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.83 × 6.02 × 10²³

We have the final answer as

<h3>4.99 × 10²³ atoms</h3>

Hope this helps you

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The mass of 69Ga is 68.7200 amu . The mass of 71Ga is 70.9200 amu .
CaHeK987 [17]
I'm not sure if what this question is asking but ill be assuming that the average molecular mass is required. An assuming that the abundance of each isotope is 50% the average molecular mass is 69.82 amu. 
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3 years ago
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2) Which liberates the most energy?
evablogger [386]

Answer: F(g)+e^-\rightarrow F^-(g)

Explanation:

Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.  

The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.

F(g)+e^-\rightarrow F^-(g)

4 0
3 years ago
How many of grams of CuSO4 are in 475ml of a 2.0M aqueous solution
Anettt [7]

Answer:

151.63 g

Explanation:

We first get the number of moles;

Moles = Molarity × volume

          = 2.0 × 0.475

          = 0.95 moles

1 mole of CuSO4 = 159.609 g/mol

Therefore;

Mass = moles × molar mas

         = 0.95 moles × 159.609 g/mol

         = 151.63 g

8 0
3 years ago
Read 2 more answers
A sample of oxide iron weighing 2.40g was heated in a stream of hydrogen until it was completely converted to the metal. If the
wlad13 [49]

Answer:

Fe₂O₃

Explanation:

To solve this question we must find the moles of Iron in 1.68g. With the difference of the masses we can find the moles of oxygen. The formula will be obtained with the ratio of both amount of moles:

<em>Moles Fe:</em>

1.68g * (1mol / 56g)  =0.03moles

<em>Moles O:</em>

2.40g-1.68g = 0.72g * (1mol/16g) = 0.045moles

The ratio O/Fe is:

0.045moles / 0.03moles = 1.5 moles. this ratio is obtained if the formula is:

<h3>Fe₂O₃</h3>
4 0
3 years ago
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