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Alona [7]
2 years ago
9

The practice of making operations "carbon neutral" is a way to offset whatever damage is being done to the environment due to gr

eenhouse gas emissions by purchasing credits from "carbon-positive" projects to balance out emissions. True or false?
Chemistry
1 answer:
Marianna [84]2 years ago
7 0

Answer:

True

Explanation:

The greenhouse effect is the process whereby there is radiation from a atmosphere planet and the planet increase the temperature of the planet's surface to a temperature above normal.In this process the Earth's atmosphere becomes thicker with the influence substances such as gases

and the radiation coming from the sun is trapped, then the Earth becomes warmer. Green house effect is seen in global warming.

Carbon neutral can be described as a process of removing huge amount of carbon dioxide from the atmosphere in order to achieve zero carbon neutrality.It is also reffered to as carbon neutrality, and this can be achieved by actions of organizations, businesses and individuals .

Carbon neutral can be achieved in two ways;

: 1.) Maintaining a balance between carbon dioxide emissions and carbon removal by means of the process called carbon offsetting

2 ) the process of removal of carbon dioxide from the atmosphere in order to balance up emissions in another place.

Carbon positive is crucial to increase the positive influence of our daily activities on climate change and our resources.

while reduce the negative effect of our activities and business on evironment.

Therefore, the practice of making operations "carbon neutral" is a way to offset whatever damage is being done to the environment due to greenhouse gas emissions by purchasing credits from "carbon-positive" projects to balance out emissions is true because the harmful gasses that is been released to the atmosphere is balance up by the carbon neutral process hence the reduction in green house effect.

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How many grams of S are in 475 g of SO2?
enot [183]

There are 237. 5 g of Sulfur,S in 475 g of SO2?

<h3 />

<h3>Calculation of grams of Sulfur</h3>

From the question, we can say that

  • The molar mass of sulfur = 32 g/mol
  • The molar mass of oxygen = 16 g/mol

Therefore,

The molar mass for SO2 = 32 + (16 × 2) g/mol  = 64 g/mol

Now,

If 1 mole of SO2 contains 1 mole of S

Then 64 g of SO2, will contain 32g of S;

Such that

475 g of SO2 will give { \frac{ 32g of S) ( 475 g of SO2)}{64 of SO2} }  = 237. 5 g of Sulfur.

Learn more about molar mass here :brainly.com/question/18291695

6 0
2 years ago
3 attempts left Check my work Click in the answer box to activate the palette. Write the balanced chemical equation where liquid
mel-nik [20]

Answer:

2 C₄H₁₀(l) + 13 O₂(g) ⇄ 8 CO₂(g) + 10 H₂O(g)

Explanation:

When a substance burns we talk about a combustion reaction. When combustion is complete the products are carbon dioxide and water, like in this case. The equation is:

C₄H₁₀(l) + O₂(g) ⇄ CO₂(g) + H₂O(g)

First, we balance the element with the largest stoichiometric coefficient (C).

C₄H₁₀(l) + O₂(g) ⇄ 4 CO₂(g) + H₂O(g)

Then, we balance H because it is in just 1 compound on each side.

C₄H₁₀(l) + O₂(g) ⇄ 4 CO₂(g) + 5 H₂O(g)

Finally, we balance O.

C₄H₁₀(l) + 6.5 O₂(g) ⇄ 4 CO₂(g) + 5 H₂O(g)

Since we want the smallest whole numbers, we multiply all coefficients by 2.

2 C₄H₁₀(l) + 13 O₂(g) ⇄ 8 CO₂(g) + 10 H₂O(g)

4 0
2 years ago
Use the data given below to construct a Born-Haber cycle to determine the second ionization energy of Ca. Δ H°(kJ) Ca(s)→Ca(g) 1
Drupady [299]

Answer :  The value of second ionization energy of Ca is 1010 kJ.

Explanation :  

The formation of calcium oxide is,

Ca(s)+\frac{1}{2}O_2(g)\overset{\Delta H_f}\rightarrow CaO(s)

\Delta H_f^o = enthalpy of formation of calcium oxide = -635 kJ

The steps involved in the born-Haber cycle for the formation of CaO:

(1) Conversion of solid calcium into gaseous calcium atoms.

Ca(s)\overset{\Delta H_s}\rightarrow Ca(g)

\Delta H_s = sublimation energy of calcium = 193 kJ

(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

Ca(g)\overset{\Delta H_I_1}\rightarrow Ca^{+1}(g)

\Delta H_I_1 = first ionization energy of calcium = 590 kJ

(3) Conversion of gaseous calcium ion into gaseous calcium ions.

Ca^{+1}(g)\overset{\Delta H_I_2}\rightarrow Ca^{+2}(g)

\Delta H_I_2 = second ionization energy of calcium = ?

(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.

O_2(g)\overset{\Delta H_D}\rightarrow OI(g)

\frac{1}{2}O_2(g)\overset{\Delta H_D}\rightarrow O(g)

\Delta H_D = dissociation energy of oxygen = \frac{498}{2}=249kJ

(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

O(g)\overset{\Delta H_E_1}\rightarrow O^-(g)

\Delta H_E_1 = first electron affinity energy of oxygen = -141 kJ

(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

O^-(g)\overset{\Delta H_E_2}\rightarrow O^{2-}(g)

\Delta H_E_2 = second electron affinity energy of oxygen = 878 kJ

(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

Ca^{2+}(g)+O^{2-}(g)\overset{\Delta H_L}\rightarrow CaO(s)

\Delta H_L = lattice energy of calcium oxide = -3414 kJ

To calculate the overall energy from the born-Haber cycle, the equation used will be:

\Delta H_f^o=\Delta H_s+\Delta H_I_1+\Delta H_I_2+\Delta H_D+\Delta H_E_1+\Delta H_E_2+\Delta H_L

Now put all the given values in this equation, we get:

-635kJ=193kJ+590kJ+\Delta H_I_2+249kJ+(-141kJ)+878kJ+(-3414kJ)

\Delta H_I_2=1010kJ

Therefore, the value of second ionization energy of Ca is 1010 kJ.

6 0
2 years ago
In chemistry class, a student conducted an investigation on the factors that affect the solubility of copper (II) sulfate (CUSO)
beks73 [17]

Answer:

See Explanation

Explanation:

The rate of a chemical reaction depends on certain factors. Some of these factors include; surface area, temperature, nature of reactants etc.

The trial that exhibits the slowest rate of dissolution of CuSO4 crystals is trial 2 because the crystals have a small surface area since the crystals were large. Also, the solution was not agitated or stirred to increase the rate of collision between the water and the CuSO4 crystals.

Increase in temperature, agitation of the reaction solution and high surface area increases the rate of collision between the water and CuSO4 crystals leading to a faster rate of dissolution. This occurs in trial 3.

3 0
2 years ago
What volume of a 0.124 M KOH solution neutralizes 23.4 mL of 0.206 M HCl solution?
alexgriva [62]
A) 15.9 mL I hope it is if not I’m sorry
6 0
3 years ago
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