Answer: The equilibrium will shift to the left to favor the reverse reaction.
Explanation:
This is a direct application of Le Chatelier's principle.
Le Chatelier's principle predicts that if a chage is introduced in a system in equilibrium, the system will react to compensate the change.
The increase in the concentration of CO, which is in the right side of the chemical equation, takes the system out of the equilibrium.
Chemically, the greater number of molecules of CO means that more CO will react to favor the reverse reaction and restore the equilibrium with the increase of molecules in the left side (CH4 and H2O).
Answer:
<em>Molar mass of the gas is 0.0961 g/mol</em>
<em></em>
Explanation:
The effusion rate of an unknown gas = 11.1 min
rate of
effusion = 2.42 min
molar mass of hydrogen = 1 x 2 = 2 g/m
molar mas of unknown gas = ?
From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.
from
= ![\sqrt{\frac{M_{h} }{M_{g} } }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BM_%7Bh%7D%20%7D%7BM_%7Bg%7D%20%7D%20%7D)
where
= rate of effusion of hydrogen gas
= rate of effusion of unknown gas
= molar mass of H2 gas
= molar mass of unknown gas
substituting values, we have
=
4.587 =
=
/4.587
= 0.31
=
= <em>0.0961 g/mol</em>
Valance electron are called
2 KOH(aq) + H2C2O4(s) → K2C2O4(aq) + 2 H2O(l) When a sample of oxalic acid (H2C2O4), which is a diprotic acid (both H-atoms are acidic), is titrated with 0.250 M potassium hydroxide solution, 24.66 mL of the potassium hydroxide solution are required to neutralize the acid. I don’t know is this gonna help but ok ._.