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Yuki888 [10]
3 years ago
11

Can a molecule have polar bonds, but still be a no polar molecule?

Chemistry
2 answers:
My name is Ann [436]3 years ago
5 0

<em><u>A molecule </u></em><em><u>can </u></em><em><u>possess polar bonds and still be nonpolar.</u></em>

I hope this helped. Have a nice day, make sure to take care of yourself. You're loved <3

Sveta_85 [38]3 years ago
5 0

Answer:

yeah, it can

Explanation:

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A pharmacist measures the mass of a powdered drug. The mass is 506 mg . What is the mass in grams? Write your answer as a decima
otez555 [7]

Answer:

0.506 g

Explanation:

we know that one miligram is equal to 0.001 g or we can say that  one gram contain thousand miligram. so,

if the mass of drug is 506 mg then to convert it into gram we have to divide 506 mg into 1000.  

8 0
3 years ago
In this reaction, what roll does the lead (II) nitrate play when 50.0 mL of 0.100M iron (III) chloride are mixed with 50.0 mL of
scoundrel [369]
Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
     2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)   
Calculating the amount of the precipitate lead(II) chloride each reactant will produce: 
     mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
                       = 0.00500mol PbCl2
     mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3)                                 = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
8 0
3 years ago
Read 2 more answers
Question 11 please HELP
Lena [83]

The answer is A or B, I would put B.

6 0
3 years ago
In descriptive scientific investigations, scientists often make observations to understand the interacting parts of a complex (b
wlad13 [49]

Answer:

Complex  System

Explanation:

Given that, a descriptive scientific investigation is one of the three main types of investigation which formulates and quantify the natural phenomenon.  This natural phenomenon oftentimes involves Complex System, such as microscopic organisms, thereby, scientists often make observations to understand the interacting parts of this COMPLEX SYSTEM

Hence, the right answer is a COMPLEX SYSTEM

8 0
3 years ago
14. What is the pH of a 0.24 M solution of sodium propionate, NaC3H502, at 25°C? (For
Murrr4er [49]

Answer:

9.1

Explanation:

Step 1: Calculate the basic dissociation constant of propionate ion (Kb)

Sodium propionate is a strong electrolyte that dissociates according to the following equation.

NaC₃H₅O₂ ⇒ Na⁺ + C₃H₅O₂⁻

Propionate is the conjugate base of propionic acid according to the following equation.

C₃H₅O₂⁻ + H₂O ⇄ HC₃H₅O₂ + OH⁻

We can calculate Kb for propionate using the following expression.

Ka × Kb = Kw

Kb = Kw/Ka = 1.0 × 10⁻¹⁴/1.3 × 10⁻⁵ = 7.7 × 10⁻¹⁰

Step 2: Calculate the concentration of OH⁻

The concentration of the base (Cb) is 0.24 M. We can calculate [OH⁻] using the following expression.

[OH⁻] = √(Kb × Cb) = √(7.7 × 10⁻¹⁰ × 0.24) = 1.4 × 10⁻⁵ M

Step 3: Calculate the concentration of H⁺

We will use the following expression.

Kw = [H⁺] × [OH⁻]

[H⁺] = Kw/[OH⁻] = 1.0 × 10⁻¹⁴/1.4 × 10⁻⁵ = 7.1 × 10⁻¹⁰ M

Step 4: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺] = -log 7.1 × 10⁻¹⁰ = 9.1

5 0
3 years ago
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