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3 years ago

How does I meter in France compare to I meter in America?

Chemistry

1 answer:

8090 [49]3 years ago

7 0

Answer: a meter is a meter

Explanation:

a meter is a certain lenght. it does not change when you're somehwere else

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Find the density of a piece of chocolate with these measurements: 2.4 g and 5.12 mL

Dahasolnce [82]

Answer:

0.46875g/ml

Explanation:

Density(p) = m / v unit - g/ml or Kg/m^3

Given

mass = 2.4g

volume = 5.12ml

p = m / v

= 2.4g / 5.12ml

= 0.46875g/ml

5 0

2 years ago

most planets have --- but none has a --- like earth does. A. a biosphere; hydrosphere., B. an atmosphere; cryosphere., C. an atm

liraira [26]

C. is the answer. i know because i had this question not that long ago.

5 0

3 years ago

Read 2 more answers

A 250 cm^3 solution containing 1,46 g of sodium chloride is added to an excess of silver nitrate solution. The reaction is given

faust18 [17]

Answer:

The mass of the precipitate that AgCl is 3.5803 g.

Explanation:

a) To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (NaCl) = 1.46 g

Molar mass of sulfuric acid = 58.5 g/mol

Volume of solution = $250 cm^3 =250 mL$

$1 cm^3= 1 ml$

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.46g\times 1000}{58.5g/mol\times 250}\\\\\text{Molarity of solution}=0.09982 M$

0.09982 M is the concentration of the sodium chloride solution.

b) $NaCl (aq)+AgNO_3 (aq)\rightarrow AgCI(s)+NaNO_3(aq)$

Moles of NaCl = $\frac{1.46 g}{58.5 g/mol}=0.02495 mol$

according to reaction 1 mol of NaCl gives 1 mol of AgCl.

Then 0.02495 moles of NaCl will give:

$\frac{1}{1}\times 0.02495 mol=0.02495 mol$ of AgCl

Mass of 0.02495 moles of AgCl:

$0.02495 mol\times 143.5 g/mol=3.5803 g$

The mass of the precipitate that AgCl is 3.5803 g.

3 0

4 years ago

Using the redox reaction below determine which element is oxidized and which is reduced. 4nh3 + 3ca(clo)2 → 2n2 + 6h2o + 3cacl2

lys-0071 [83]

The oxidation number of elements in equation below are,

4NH₃ + 3Ca(ClO)₂ → 2N₂ + 6H₂O + 3CaCl₂

O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
O.N of N in N₂ = 0
O.N of Cl in Ca(ClO)₂ = +1
O.N of Cl in CaCl₂ = -1

Oxidation:
Oxidation number of Nitrogen is increasing from -3 (NH₃) to 0 (N₂).

Reduction:
Oxidation number of Cl is decreasing from +1 [Ca(ClO)₂] to -1 (CaCl₂).

Result:
<span>N is oxidized and Cl is reduced.</span>

6 0

3 years ago

Read 2 more answers

A model of an ideal gas is shown here. A student designs an experiment to test the impact of increasing the pressure on the syst

k0ka [10]

A. As pressure on the gas increases, the volume and temperature will both decrease

6 0

3 years ago