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Bad White [126]
3 years ago
9

What is the mass in grams of 1.24 mol of water

Chemistry
1 answer:
ki77a [65]3 years ago
4 0
Mass of H2O=2.01568g+15.9994g=18.01508gmol H2O.
Step 2: Multiply 1.24 mol H2O with the molecular mass. 1.24 mol H2O x 18.01508gmol H2O = 22.3 g H2O.
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Which would least strongly attract electrons from other atoms in a compound?
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The concept we are looking for here is electronegativity. This concept is a measure of how strong an atom or element can attract a pair, that is bonding, of electrons to itself. 

Fluorine is the element or atom of the greatest electronegativity. Electronegativity would increase as we move left to right of the periodic table. 

 
4 0
3 years ago
construct the lewis structure of oo . draw the structure by placing atoms on the grid and connecting them with bonds. include al
ankoles [38]

In Lewis dot structures, you draw the atom in the center and then surround the atom with its valence electrons. The Lewis structure for O is as shown in the attached diagram.

<h3>What is the Lewis structure of O ?</h3>

Lewis Structure of an atom of oxygen contains 6 electrons in the valence shell. Four valence electrons exist in lone pairs. It implies that oxygen atom must participate in two single bonds or one double bond in order to have an octet configuration.

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brainly.com/question/1525249

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8 0
1 year ago
Determine the empirical formula for a compound that contains 15.8% carbon and 84.2% sulfer
nydimaria [60]

Answer:

Carbon Disulfide CS2

Explanation:

6 0
3 years ago
Balance the following redox reaction occurring in an acidic solution. The coefficient of Mn2+(aq) is given. Enter the coefficien
Vadim26 [7]

Answer:

_5_ AsO2−(aq) + 3 Mn2+(aq) + _2_ H2O(l) → _5_ As(s) + _3_ MnO4−(aq) + _4_ H+(aq)

Explanation:

Step 1:

The unbalanced equation:

AsO2−(aq) + 3 Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

Step 2:

Balancing the equation.

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 4 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 4 in front of H+ as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + 4H+(aq)

There are 5 atoms of As on the left side and 1 atom on the right side. It can be balance by putting 5 in front of As as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → 5As(s) + 3MnO4−(aq) + 4H+(aq)

Now the equation is balanced

7 0
3 years ago
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