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andrey2020 [161]
4 years ago
15

SOMEONE PLEASE HELP ME THIS IS DUE TOMORROW!! I WILL MARK YOU AS A BRAINLIEST IF ANSWERED NOW!!

Chemistry
1 answer:
AnnZ [28]4 years ago
6 0
K= [Ar] 4s^1

Pb= [Xe]  6s^2 5d^10 6p^2

Sc= [Ar] 4s^2 3d^1

Ra= [Rn] 7s^2

O= [He] 2s^2 2p^4

Ag= [Kr] 5s^2 4d^9

Ru= [Kr] 5s^1

Ce=  [Xe] 6s^2 5d^1 4f^1

I= [Kr] 5s^2 4d^10 5p^5

F= [He] 2s^2 2p^5



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Calculate the pKa of lactic acid (CH3CH(OH)COOH) given the following information. 3.005 grams of potassium lactate are added to
snow_lady [41]

Answer:

\displaystyle \text{p} K_a \approx 3.856

Explanation:

Because 3.005 grams of potassium lactate is added to 100. mL of solution, its concentration is:


\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right]  & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}

By solubility rules, potassium is completely soluble, so the compound will dissociate completely into potassium and lactate ions. Therefore, [KC₃H₅O₃] = [C₃H₅O₃⁺]. Note that lactate is the conjugate base of lactic acid.

Recall the Henderson-Hasselbalch equation:

\displaystyle \begin{aligned}\text{pH} = \text{p}K_a + \log \frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]} \end{aligned}

[Base] = 0.234 M and [Acid] = 0.500 M. We are given that the resulting pH is 3.526. Substitute and solve for p<em>Kₐ</em>:

\displaystyle \begin{aligned} (3.526) & = \text{p}K_a + \log \frac{(0.234)}{(0.500)} \\ \\ 3.526 & = \text{p}K_a + (-0.330) \\ \\ \text{p}K_a & = 3.856\end{aligned}

In conclusion, the p<em>Kₐ </em>value of lactic acid is about 3.856.

5 0
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What is biological function?
Alika [10]

Answer:

Biological Functions: processes and structures by which organisms adjust to short-term or long-term changes in their environment

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Under which conditions of temperature and pressure does a real gas behave most like an ideal gas
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At higher temperature, and lower pressure. 
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Masja [62]

Answer:

May be the instrument is incorrect or may be error in it.

Explanation:

The copper have not been detected by this test because the test may be not for the detection of copper, may be it is used for identification of another minerals. If there is copper in the lake sample but can't be detected in the test so it means that the instrument which is used for detection is not the right one  or having error in that instrument. Every mineral has a specific type of instrument that detect its presence, if we use incorrect instrument for the mineral then we can't detect the presence of that specific mineral.

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Explanation:

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